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BaLLatris [955]
3 years ago
7

What is the range of the function on the graph?

Mathematics
1 answer:
saw5 [17]3 years ago
6 0

Answer:

IT AMOUNG SUS DEZZ balls

Step-by-step explanation:

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George bought socks for "$"300 and planned to sell them for $6 a pair. write an inequality to find the minimum number of socks h
Anit [1.1K]

The inequality <u>6s - 300 > 210</u> represents the minimum number of socks (s) when George bought socks for "$"300 and planned to sell them for $6 a pair, and want to make a profit of more than 210.

In the question, we are given that George bought socks for $300.

Therefore, George's total cost = $300.

We assume the number of pairs of socks George sells to be s.

The unit price per pair quoted by George = $6

Therefore, George's total sales = $6s.

We know that the profit over a transaction is given as the difference between sales and costs, that is,

The profit = The total sales - the total costs,

or, profit = 6s - 300.

In the question, we are required to make a profit of more than 210.

This can be shown by the inequality,

6s - 300 > 210.

Thus, the inequality <u>6s - 300 > 210</u> represents the minimum number of socks (s) when George bought socks for "$"300 and planned to sell them for $6 a pair, and want to make a profit of more than 210.

Learn more about inequalities at

brainly.com/question/24372553

#SPJ4

5 0
2 years ago
Draw a shape using a rectangle and a triangle
navik [9.2K]
You can draw a house :)
7 0
3 years ago
Convert 1.5 kg to g.
KiRa [710]
The answer is 1500g. There are 1000 grams in a kilogram so 1.5 x 1000 = 1500.
6 0
3 years ago
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A scientist is growing bacteria in a lab for study. One particular type of bacteria grows at a rate of y=2t^2+3t+500. A differen
Leya [2.2K]

ANSWER

Approximately after 15 minutes.

EXPLANATION

The growth rate of the first bacteria is

y = 2 {t}^{2}   + 3t + 500

The growth rate of the first bacteria :

y = 3 {t}^{2}  + t + 300

To find the time that, there will be an equal number of bacteria, we equate the two equation;

3 {t}^{2}  + t + 300 = 2 {t}^{2}   + 3t + 500

3 {t}^{2}  - 2 {t}^{2}   + t  - 3t +  300 - 500 =00

{t}^{2}  - 2t  - 200= 0

We solve for t to get,

t = 15.177

Or

t =  - 13.177

We discard the negative value.

This implies that,

t \approx15

8 0
4 years ago
Solve 1-12 or any of them please.
ladessa [460]
1. y = 4x - 3
2. y = -x + 4
3. y = 1/3x +1
4. y = ----
5. y = 1/7x + 2
6. y = -4x + 2.75
7. y = 3x + 5
8.
9.
10.
11.
12.

3 0
3 years ago
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