Here we have , If a and b are both integers and b does not equal 0, then -(a/b) = (-a)/b = a/(-b) Choose two values for a and b. We need to find if those values make the equation true . Let's find out:

We have the following equation:

-(a/b) = (-a)/b = a/(-b) , Let a=4 , b=3 , So

⇒ $-(a/b) = (-a)/b = a/(-b)$

⇒ $-\frac{a}{b} = \frac{-a}{b} = \frac{a}{-b}$

⇒ $-\frac{4}{3} = \frac{-4}{3} = \frac{4}{-3}$

⇒ $-\frac{4(-1)}{3} = \frac{-4(-1)}{3} = \frac{4(-1)}{-3}$ { Multiplying by -1 }

⇒ $\frac{4}{3} = \frac{4}{3} = \frac{4}{3}$

Therefore , These values make the equation true .

7 0

3 years ago

5. There are 29 students available to represent the upperclassmen at a fair.

Stels [109]

Answer:

senior and junior? that would be a perfect 100%, 29/29

Step-by-step explanation:

Unless I'm incorrect, this question states the probability of BOTH a senior AND junior being chosen, which would be 100% or again, 29/29

7 0

3 years ago

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