What is the ratio of 1.5kg:500g:1kg

A polygon is shown: A polygon MNOPQR is shown. The top vertex on the left is labeled M, and rest of the vertices are labeled clo

Mashcka [7]

Answer:

The area of polygon MNOPQR = Area of a rectangle that is 15 square units + Area of a rectangle that is 2 square units.

Step-by-step explanation:

We are given that a polygon MNOPQR is shown. The top vertex on the left is labeled M, and the rest of the vertices are labeled clockwise starting from the top-left vertex labeled, M. The side MN is parallel to side QR. The side MR is parallel to side PQ.

The side MN is labeled as 5 units. The side QR is labeled as 7 units. The side MR is labeled as 3 units, and the side NO is labeled as 2 units.

Firstly, we will draw a perpendicular line from point O which meets the line RQ at point T. Now, the polygon MNOPQR is divided into two rectangles MNTR and OPQT.

As we know that the area of the rectangle = $\text{Length of rectangle} \times \text{Breadth of rectangle}$

In the rectangle MNTR, the length (MN) = 5 units and the breadth (MR) = 3 units.

So, the area of the rectangle MNTR = $\text{Length (MN)} \times \text{Breadth (MR)}$

= $5 \times 3$ = 15 square units

Now, as we know that in rectangle MNTR, the side NT = 3 units and the side NO is labeled as 2 units. This means that the side OT = NT - NO = 3 units - 2 units = 1 unit

Similarly, the side QR is labeled as 7 units and the side RT is labeled as 5 units. This means that the side TQ = QR - RT = 7 - 5 = 2 units

Now, in the rectangle OPQT, the length (TQ) = 2 unit and the breadth (OT) = 2 units.

So, the area of the rectangle OPTQ = $\text{Length (TQ)} \times \text{Breadth (OT)}$

= $2 \times 1$ = 2 square units

Hence, the area of polygon MNOPQR = Area of a rectangle that is 15 square units + Area of a rectangle that is _2_ square units.

3 0

3 years ago

Helllpppppppppppppppppppppppp

Ivahew [28]

Answer:

C

Step-by-step explanation:

it's C

sorry if I am wrong

6 0

3 years ago

The point plotted on the number line is StartRoot x EndRoot.

miv72 [106K]

Answer:

i think its 17

Step-by-step explanation:

i said i think

3 0

3 years ago

Read 2 more answers

What is the solution to the quadratic inequality? 6x2≥5−13x

Sav [38]

Answer:

X>1

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The American Water Works Association reports that the per capita water use in a single-family home is 63 gallons per day. Legacy

Debora [2.8K]

Answer:

$t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784$

$df=n-1=28-1=27$

$p_v =P(t_{(27)}$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=60$ represent the sample mean

$s=8.9$ represent the sample standard deviation

$n=28$ sample size

$\mu_o =68$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is less than 63, the system of hypothesis would be:

Null hypothesis: $\mu \geq 63$

Alternative hypothesis: $\mu < 63$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{60-63}{\frac{8.9}{\sqrt{28}}}=-1.784$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=28-1=27$

Since is a one side lower test the p value would be:

$p_v =P(t_{(27)}$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the true mean is less than 63 gallons per day at 1% of signficance.

5 0

4 years ago