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Lena [83]
3 years ago
15

Help me plzzzz (x+1)^2 -3(x+2) If you could give an explanation that would be great!

Mathematics
1 answer:
Margarita [4]3 years ago
4 0

Answer:

x^2-x-5

Step-by-step explanation:

1. expand the square

(+1)(+1)−3(+2)

2. distribute

(+1)+1(+1)−3(+2)

3. distribute

^2++1(+1)−3(+2)

4. multiply by 1

^2+++1−3(+2)

5. combine like terms

^2+2+1−3(+2)

6. distribute

^2+2+1−3−6

7. subtract the numbers

^2+2−5−3

8. combine like terms

^2−−5

9. gg you are done

^2−−5

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Answer:

A: P = 20n +415

B: P = 20t + 375

C: Both equations agree, and in 2018 there will be about 535 wolves

D: The advantage of defining the input variable is that it helps simplify the calculation and makes it more intuitive.

Step-by-step explanation:

<h3>A:</h3>

P = <u>Number of wolves</u>

n = <u>number of years since 2012</u>

<em>we know </em><em>in 2012</em><em> there were </em><u><em>415 wolves in the sanctuary</em></u><em>, and that the </em><em>sanctuary </em><em>has been </em><em>growing about </em><u><em>20</em></u><u><em> wolves </em></u><u><em>a year.</em></u>

<u><em></em></u>

<h3>P = 20n + 415</h3>

we know this is correct because we are trying to create an equation that represents the number of wolves(p) throughout the years(n), so we are trying to figure out what P equals. We know that the sanctuary grows about <u>20</u> wolves a year, and n is the number of years since 2012. As well as obviously,<u> we add 415 to our equation because there is </u><u>already 415 wolves in the sanctuary.</u>

<h3>B:</h3>

P = <u>Number of wolves</u>

t = <u>number of years since 2010</u>

x = <u>unknown variable(number of wolves in 2010)</u>

<h3>P = 20t + x</h3>

Here we are trying to identify what x is,<u> in 2012 there was 415, each year the number of wolves grew by 20.</u>

<h3>P = 20(2) - 415</h3>

P = 40 - 415 = 375

<u>We now know there were 375 wolves in 2010</u>

<h3>Hence our equation is P = 20t + 375</h3>

<h3>C:</h3><h3>First let's plug in our first equation</h3>

P = 20n + 415

(To find n all we do is subtract 2018 and 2012, which equals 6.)

P = 20(6) + 415

(Solve)

P = 120 + 415

<h3>P = 535</h3>

<em>Our first equation tells us that in 2018 there will be 535 wolves.</em>

<em></em>

<h3>Plug in our second equation</h3>

P = 20t + 375

(To find t all we do the same thing we did last time except now we subtract 2018 from 2010, which equals 8)

P = 20(8) + 375

P = 160 + 375

<h3>P = 535</h3>

<h2>Both our equations agree, and in 2018 there will be 535 wolves.</h2>

<h3>D:
</h3>

The advantage of defining the input variable is that it helps simplify the calculation and makes it more intuitive.

7 0
2 years ago
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