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anastassius [24]
3 years ago
10

Help me on 5. Answer please

Mathematics
1 answer:
Ket [755]3 years ago
5 0

Answer:

5/8

Step-by-step explanation:

1 - 3/8

1 + (-3/8)

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A rectangle is 9ft long and 40 in wide what is its area in square feet?
Irina-Kira [14]
The answer is 360 sqft

6 0
2 years ago
What is the equation of the following line written in slope intercept form? (-5,-1)
solmaris [256]

Answer:

\large\boxed{y=-\dfrac{2}{3}x-\dfrac{13}{3}}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

From the graph we have two points (-5, -1) and (-2, -3).

<em>Look at the picture</em>.

Calculate the slope:

m=\dfrac{-3-(-1)}{-2-(-5)}=\dfrac{-2}{3}=-\dfrac{2}{3}

Put it to the equation in slope-intercept form:

y=-\dfrac{2}{3}x+b

We can't read the y-intercept from the graph. Therefore put the coordinates of the point (-5, -1) to the equation and calculate <em>b</em>:

-1=-\dfrac{2}{3}(-5)+b

-1=\dfrac{10}{3}+b         <em>subtract 10/3 from both sides</em>

-\dfrac{3}{3}-\dfrac{10}{3}=b\to b=-\dfrac{13}{3}

Finally:

y=-\dfrac{2}{3}x-\dfrac{13}{3}

4 0
3 years ago
Convert the following fraction to a decimal.
Nookie1986 [14]
I think it’s C but I could be wrong but I don’t think I am
6 0
2 years ago
Eliza is two years younger than half her bro Juan age write an equation to represent Eliza’s age ; if Juan is 6 how old is Eliza
cricket20 [7]

Answer:

Eliza is 1

Step-by-step explanation:

If Eliza is 2 years younger than 1/2 her brothers age and Juan is 6.

  • - divide 6 by 2 (6÷2=3)
  • - Take 3 away from 2 ( 3-2=1)

So that means Eliza would be 1

6 0
3 years ago
Help with all three IM CONFUSED
icang [17]

Answer:

How does y vary with x?

This is called direct variation and to find proportionality, we use the formula y/x = K

Step-by-step explanation:

The first table's results would look like:

6:15

12:30

18:45

24:60

30:75

To do these, you divide the y values by the constant to receive x.

If you need more help, you message me :) Good luck with your work!

5 0
3 years ago
Read 2 more answers
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