Ask question

Ask question

All categories

3 years ago

12

Round 45.983 to the nearest whole number, tenth and hundredth.

1 answer:

Nady [450]3 years ago

8 0

Answer:

46

Step-by-step explanation:

if you round to the nearest whole, look at the tenths place and if it is bigger than 4, then then you round up, like 7043.7305 to 7044 but if the tenths place is smaller than 5, the number stays the same but the decimal part is gone, like 350.24569405 to 350.

You might be interested in

Which of the following fractions is equivalent to 0.45? 4/5 2/5 9/20 9/200

exis [7]

45/100
Simplify the fraction by diving by the largest possible factor
45 divided by 5 = 9
100 divided by 5 = 20
9/20
9/20 = 0.45

4 0

3 years ago

Simplify 4^9/4^3<br> can someone help me with this?

zaharov [31]

Answer:

4096

Step-by-step explanation:

Need to know how you got it? Comment on this answer.

4 0

3 years ago

The sum of 5 and y is at least 18?

Mashcka [7]

Answer:

y=13

Step-by-step explanation:

5+13=18

7 0

3 years ago

Read 2 more answers

Find the integration of (1-cos2x)/(1+cos2x)

slega [8]

Given:

The expression is:

$\dfrac{1-\cos 2x}{1+\cos 2x}$

To find:

The integration of the given expression.

Solution:

We need to find the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ .

Let us consider,

$I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx$

$I=\int \dfrac{2\sin^2x}{2\cos^2x}dx$ $[\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]$

$I=\int \dfrac{\sin^2x}{\cos^2x}dx$

$I=\int \tan^2xdx$ $\left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]$

It can be written as:

$I=\int (\sec^2x-1)dx$ $[\because 1+\tan^2 \theta =\sec^2 \theta]$

$I=\int \sec^2xdx-\int 1dx$

$I=\tan x-x+C$

Therefore, the integration of $\dfrac{1-\cos 2x}{1+\cos 2x}$ is $I=\tan x-x+C$ .

8 0

3 years ago

I need the answer to a parts I-iii and the answer to b

fomenos

Answer:

a)

i) Mean = 72

ii) Median = 72

iii) Mode = 72

b)

69, 70, 71, 72, 72, 72, 73, 74, 75

Step-by-step explanation:

<u>a. To find mean, median and mode</u>

It is given that all the 9 students get 72 marks.

Therefore the data set be,

72, 72, 72, 72, 72, 72, 72, 72 72

<u>i) mean </u>= (sum of data)/(total number of data)

= (9 * 72)/9 = 9

<u>ii) Median </u>- Central data in the data set when arranging ascending or descending order

72, 72, 72, 72, 72, 72, 72, 72 72

Median = 72

<u>iii) Mode </u>- Most repeating data in the data set

Here mode = 72

<u>b). To find a data set</u>

69, 70, 71, 72, 72, 72, 73, 74, 75

Here Mean, mode and median are all 72

3 0

3 years ago