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dimaraw [331]
3 years ago
13

Write ellipse in standard form

Mathematics
1 answer:
irakobra [83]3 years ago
4 0
Ellipse in standard form
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Amanda's jewelry box is in the shape of a cube that has 6 inche edges. What is the volume of Amanda's jewelry box?
Mekhanik [1.2K]
To find the volume of any cube you need to know the length, width and height. The formula to find the volume multiplies the length by the width by the height. The good news for a cube is that the measure of each of these dimensions is exactly the same. Therefore, you can multiply the length of any side three times, so 6 x 6 x 6 is just 216 in.
4 0
3 years ago
One card is randomly selected from a deck of cards find the odds against drawing a seven
Stella [2.4K]

Answer:

\frac{3}{4}

Step-by-step explanation:

Probability of getting a 7 + Probability of not getting a 7 = 1.

Odds against drawing a 7 = Probability of not getting a 7.

We could calculate the probability of getting a 7 and subtract 1 from it to get the answer.

There a four sevens in a deck of card, one of each kind.

Probability of getting a 7 = $ P(7) = \frac{4}{52} = \frac{1}{13} $

$ \implies P(not \hspace{1mm} getting \hspace{1mm} a \hspace{1mm} 7) = 1 - P(7) $

$ \implies $ P(not getting a 7) $ = 1 - \frac{1}{13} = \frac{12}{13} $

4 0
4 years ago
n a group of 40 people, 10 people are healthy. The 30 unhealthy people have either high blood pressure, high cholesterol, or bot
aalyn [17]

Answer:

If a person is randomly selected from this group, the probability that they have both high blood pressure and high cholesterol is P=0.25.

Step-by-step explanation:

We can calculate the number of people from the sample that has both high blood pressure (HBP) and high cholesterol (HC) using this identity:

N(\text{HBP or HC})=N(\text{HBP})+N(\text{HC})-N(\text{HBP and HC})\\\\\\ N(\text{HBP and HC})=N(\text{HBP})+N(\text{HC})-N(\text{HBP or HC})\\\\\\ N(\text{HBP and HC})=15+25-30=10

We can calculate the probability that a random person has both high blood pressure and high cholesterol as:

P(\text{HBP and HC})=\dfrac{10}{40}=0.25

3 0
3 years ago
Triangle J K L is shown. Angle J K L is 120 degrees and angle K L J is 40 degrees. The length of K L is 2 and the length of J L
Veseljchak [2.6K]

Answer:

k \approx 5$ units

Step-by-step explanation:

In Triangle JKL

\angle K=120^\circ\\\angle L=40^\circ\\KL=2\\JL=k

We want to determine the approximate value of k using the law of sines.

\angle J+\angle K+\angle L=180^\circ $ (Sum of angles in a \triangle)\\\angle J+120^\circ+40^\circ=180^\circ \\\angle J=180^\circ-(120^\circ+40^\circ)=20^\circ

Using Law of Sines

\dfrac{k}{\sin K} =\dfrac{j}{\sin J} \\\dfrac{k}{\sin 120} =\dfrac{2}{\sin 20} \\k=\sin 120 \times \dfrac{2}{\sin 20}\\k=5.06\\k \approx 5$ units

7 0
3 years ago
Read 2 more answers
Pls help
VikaD [51]
Answer: both

Unless you mistyped the first number and it’s actually -3 instead of 3 than b is the answer.

To see if they make a function you can graph all the coordinates and do the line test. Or you can look at all the numbers and see if any of the ordered pair have repeating x values. If they do, it’s not a function.

Remember, it’s (x,y) and if any X values repeat, it’s NOT a function
6 0
3 years ago
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