The 2s subshell holds a maximum of 2 electrons, and the 2p subshell holds a maximum of 6 electrons. Which means that the second shell can hold a maximum of only 8 electrons (2+6 = 8)
The other answer is wrong, the question asks how many will be on the second sheel which is B, 4, as the first valence shell holds two, 6-2=4 meaning there will definatly be 4 electrons on the second valence shell
