All categories

3 years ago

Complete the table for the given function.

Mathematics

2 answers:

Nataly_w [17]3 years ago

8 0

The answer is, -3, -2, 1, 6

timofeeve [1]3 years ago

6 0

the answer is a. -3, -2, 1, 6

You might be interested in

9. What date will it be? (One is done for you)

Licemer1 [7]

Answer:

A. 5 days after 15 June - June 20

B. 10 days before Independence day - 5 August

C. 7 days before 8 January - 1 January

D. 3 days before Republic day - 23 January

E. 14 days after 16 July - 30 july

F. 20 days after 1 August - 21 August

3 0

3 years ago

Which expression shows the sum of the polynomials with like terms grouped together? (8x+3z-8z^2)+(4y-5z)

Andrews [41]

It’s (-8z^2 +8x +4y -2z)

Hope it helps

3 0

3 years ago

Simplify the expression (m^3)^-1 (x^2)^5

Katyanochek1 [597]

(m^3)^-1 (x^2)^5 = (m^-3) (x^10) = x^10 / m^3

6 0

3 years ago

Find IG in the image below .

Ierofanga [76]

Step-by-step explanation:

$ig =2 \times yx = 2 \times 11 = 22$

6 0

3 years ago

You can model the population of a certain city between 1955-2000 by the radical function

OverLord2011 [107]

Complete Question:

You can model the population of a certain city between 1955-2000 by the radical function

P(x) = 55,000 sqrt x-1945

Using this model, in which year was the population of that city 275,000?

Answer:

In 1970 population of that city is 275,000

Solution:

Given that,

You can model the population of a certain city between 1955-2000 by the radical function :

$P(x) = 55000\sqrt{x - 1945}$

To find: year in which was the population of that city 275,000

Therefore,

x = ?

P(x) = 275000

Thus we get,

$275000 = 55000\sqrt{x - 1945}\\\\Divide\ both\ sides\ by\ 55000\\\\\frac{275000}{55000} = \sqrt{x-1945}\\\\5 = \sqrt{x - 1945}\\\\Take\ square\ on\ both\ sides\\\\25 = x - 1945\\\\x = 1945 + 25\\\\x = 1970$

Thus, in 1970 population of that city is 275,000

4 0

3 years ago