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3 years ago

12

In circle Z. what is mz2?

2 answers:

elena55 [62]3 years ago

4 0

Answer : 140 degrees
explanation:

Westkost [7]3 years ago

3 0

Answer:

140°

Step-by-step explanation:

$m \angle \: 2 = \frac{1}{2} \times \bigg(133 \degree + 147 \degree \bigg) \\ \\ m \angle \: 2 = \frac{1}{2} \times 280 \degree \\ \\ \huge \red { \boxed{m \angle \: 2 = 140 \degree }}$

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3 years ago

Find the 75th term of the arithmetic sequence -17, -13, -9....

Sphinxa [80]

Answer:

The 75th term of the arithmetic sequence -17, -13, -9.... is:

$a_{75}=279$

Step-by-step explanation:

Given the sequence

$-17, -13, -9....$

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

computing the differences of all the adjacent terms

$-13-\left(-17\right)=4,\:\quad \:-9-\left(-13\right)=4$

The difference between all the adjacent terms is the same and equal to

$d=4$

The first element of the sequence is:

$a_1=-17$

now substitute $d=4$ and $a_1=-17$ in the nth term of the sequence

$a_n=a_1+\left(n-1\right)d$

$a_n=4\left(n-1\right)-17$

$a_n=4n-21$

Now, substitute n = 75 in the $a_n=4n-21$ sequence to determine the 75th sequence

$a_n=4n-21$

$a_{75}=4\left(75\right)-21$

$a_{75}=300-21$

$a_{75}=279$

Therefore, the 75th term of the arithmetic sequence -17, -13, -9.... is:

$a_{75}=279$

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3 years ago