<span>The following indicate that a linear model is not the best fit for a dataset:
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• Scatterplot shows a curve pattern.
• Residual plot shows no pattern.
• Correlation coefficient is close to 1 or –1.
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</span>I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!<span><span>
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Answer:
Set A's standard deviation is larger than Set B's
Step-by-step explanation:
Standard deviation is a measure of variation. One way to judge the value of standard deviation is by looking at the range of the data. In general, a dataset with a smaller range will have a smaller standard deviation.
The range of data Set A is 25-1 = 24.
The range of data Set B is 18-8 = 10.
Set A's range is larger, so we expect its standard deviation to be larger.
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The standard deviation is the root of the mean of the squares of the differences from the mean. In Set A, the differences are ±12, ±11, ±10. In Set B, the differences are ±5, ±3, ±1. We don't actually need to compute the RMS difference to see that it is larger for Set A.
Set A's standard deviation is larger than Set B's.
Answer:
Refer to the picture that given
Step-by-step explanation:
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Answer:
00:13 mm:ss
Step-by-step explanation:
There are 60 seconds in a minute. This fact can be used to convert the time period(s) to minutes and seconds either before or after you do the subtraction.
<h3>Difference</h3>
It is often convenient to do arithmetic with all of the numbers having the same units. Here, we are given two values in seconds and asked for their difference.
100 s - 87 s = (100 -87) s = 13 s
The difference between the two time periods is 0 minutes and 13 seconds.
<h3>Conversion</h3>
If you like, the numbers can be converted to minutes and seconds before the subtraction. Since there are 60 seconds in a minute, the number of minutes is found by dividing seconds by 60. The remainder is the number of seconds that will be added to the time in minutes:
87 seconds = ⌊87/60⌋ minutes + (87 mod 60) seconds
= 1 minute 27 seconds
100 seconds = ⌊100/60⌋ minutes + (100 mod 60) seconds
= 1 minute 40 seconds
Then the difference is found in the same way we would find a difference involving different variables. (A unit can be treated as though it were a variable.)
(1 min 40 s) -(1 min 27 s) = (1 -1 min) + (40-27 s) = 0 min 13 s
The difference between the two time periods is 0 minutes and 13 seconds.
Answer:
No Solution.
Step-by-step explanation:
-(6x-5)=-6x+13
-6x+5=-6x+13
-6x-(-6x)+5=13
-6x+6x+5=13
0+5=13
5=13