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3 years ago

Find the area of this shape. The area of this shape is _______ square centimeters.

Mathematics

2 answers:

vesna_86 [32]3 years ago

5 0

Answer:

Step-by-step explanation:

area =(4+4+4)/2×2+1/2×(4+4)×5.75

=12+23.00

=35 sq.cms.

rewona [7]3 years ago

4 0

Step-by-step explanation:

Area of triangle = $\frac{1}{2}$ (b*h)

Area of rectangle = b*h

$A(big-triangle) = \frac{1}{2} (5.75*4)$

$A(big-triangle) = \frac{1}{2}(23)$

$A(big-triangle) = 11.5$

Since there are two big triangles, then we can multiply 11.5 by 2.

11.5 * 2 = 23

$A(small-triangle) = \frac{1}{2}(2*2)$

$A(small-triangle) = \frac{1}{2} (4)$

$A(small-triangle) = 2$

Since there are two small triangles, then we can multiply 2 by 2.

2 * 2 = 4

$A(rectangle)= 4 * 2$

$A(rectangle) = 8$

Now, we can add up all of the areas so we can find the total area of the entire shape.

23 + 4 + 8 = 35

So, the area of the entire shape is 35 square cm.

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Brainliest for correct answer A. 2 B. -2 C. 1/2 D. -1/2

seropon [69]

Answer:

B) -2

Step-by-step explanation:

I got the slope by using two points on the line (0,7) and (4,-1)

Slope=y2-y1/x2-x1

(7--1)/(0-4)

8/-4

I then simplified 8/-4 to -2

You could also solve by finding the rise over run for two points on the line.

The rise is 2 and the run is -1, making it 2/-1 or -2

8 0

3 years ago

Read 2 more answers

Point A, located at (-11, - 7) on the coordinate plane, is reflected over the x-axis to form point B. Then point B is reflected

hram777 [196]

Answer:

Answer: B(-11,7) C(11,7)

Step-by-step explanation:

Reflections In The Coordinate Plane

Reflect over the x-axis:

When we reflect a point over the x-axis, the x-coordinate remains the same, but the y-coordinate is mapped to its opposite.

The reflection of the point (x,y) over the x-axis is the point (x,-y).

Reflect over the y-axis:

When reflecting a point over the y-axis, the y-coordinate remains the same, but the x-coordinate is mapped to its opposite (its sign is changed).

The reflection of the point (x,y) across the y-axis is the point (-x,y).

Point A is at (-11,-7). When reflected over the x-axis, it maps to Point B located at B(-11,7).

Point B is now reflected over the y-axis and maps to C(11,7).

Answer: B(-11,7) C(11,7)

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3 years ago

Identify the correct corresponding parts

andrey2020 [161]

Answer:

The correct corresponding part is;

$\overline {CB}$ ≅ $\overline {CD}$

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment $\overline {CA}$ is congruent to $\overline {CE}$ ( $\overline {CA}$ ≅ $\overline {CE}$ )

Segment $\overline {CB}$ is congruent to $\overline {CD}$ ( $\overline {CB}$ ≅ $\overline {CD}$ )

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment $\overline {AB}$ is congruent to $\overline {DE}$ ( $\overline {AB}$ ≅ $\overline {DE}$ ) by CPCTC

Segment $\overline {AE}$ bisects $\overline {BD}$

Segment $\overline {BD}$ bisects $\overline {AE}$

Therefore, the correct option is $\overline {CB}$ ≅ $\overline {CD}$

3 0

3 years ago

Which angle in triangle DEF has the largest measure?

nordsb [41]

Answer:

D is the largest angle

Step-by-step explanation:

The angle opposite the largest side is the largest and the angle opposite the smallest side is the smallest.

Since 12 is the largest side, angle D is the largest

8 is the smallest side, F is the smallest angle

7 0

3 years ago

What is the value of c such that the line y=2x+3 is tangent to the parabola y=cx^2

satela [25.4K]

The value of $c$ such that the line $y = 2\cdot x + 3$ is tangent to the parabola $y = c\cdot x^{2}$ is $-\frac{1}{3}$ .

If $y = 2\cdot x + 3$ is a line tangent to the parabola $y = c\cdot x^{2}$ , then we must observe the following condition, that is, the slope of the line is equal to the first derivative of the parabola:

$2\cdot c \cdot x = 2$ (1)

Then, we have the following system of equations:

$y = 2\cdot x + 3$ (1)

$y = c\cdot x^{2}$ (2)

$c\cdot x = 1$ (3)

Whose solution is shown below:

By (3):

$c =\frac{1}{x}$

(3) in (2):

$y = x$ (4)

(4) in (1):

$y = -3$

$x = -3$

$c = -\frac{1}{3}$

The value of $c$ such that the line $y = 2\cdot x + 3$ is tangent to the parabola $y = c\cdot x^{2}$ is $-\frac{1}{3}$ .

We kindly invite to check this question on tangent lines: brainly.com/question/13424370

3 0

2 years ago