Answer:
the least integer for n is 2
Step-by-step explanation:
We are given;
f(x) = ln(1+x)
centered at x=0
Pn(0.2)
Error < 0.01
We will use the format;
[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01
So;
f(x) = ln(1+x)
First derivative: f'(x) = 1/(x + 1) < 0! = 1
2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1
3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2
4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6
This follows that;
Max|f^(n+1) (c)| < n!
Thus, error is;
(n!/(n + 1)!) × 0.2^(n + 1) < 0.01
This gives;
(1/(n + 1)) × 0.2^(n + 1) < 0.01
Let's try n = 1
(1/(1 + 1)) × 0.2^(1 + 1) = 0.02
This is greater than 0.01 and so it will not work.
Let's try n = 2
(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267
This is less than 0.01.
So,the least integer for n is 2
<span>Part
A: Solve A = (x + 23) for x.
A = x + 23
=> A - 23 = x + 23 - 23
=> A - 23 = x
=> x = A - 23 <------- answer
Part B: Determine the value of x
when A = 108
Replace the value of A in the expression x = A - 23
x = 108 - 23 = 75
x = 75 <------- answer
Part C: Solve -np - 90 > 30 for n.
-np - 90 > 30
=> -np + np - 90 >30 + np
=> - 90 > 30 + np
=> -90 - 30 > 30 - 30 + np
=> -120 > np
=> np < - 120 <----- answer
</span>
Answer:
C(x) = 
Step-by-step explanation:
Data provided in the question:
Area of the field = 3600 square feet
Fencing charges = $3.50 per foot
Let the side along the river be 'x' feet and the other side of the 'B'
now,
Area of rectangle = Bx = 3600 square feet
or
B = 
feet
and total length to be fenced = x + 2B
therefore,
Total cost of fencing = Fencing charges × total length to be fenced
or
Total cost of fencing = $3.50 × ( x + 2B )
substituting the value of B from (1)
Total cost of fencing, C(x) = 
or
C(x) =
21/56 which reduces to 3/8 ...or if u need a percent, it is 37.5%
Answer:
45
Step-by-step explanation:
