Is there a relationship between area or perimeter of a rectangle
1 answer:
Hello,
For a given perimeter (P) there are an infinity of Area (A)
Let's say x the length, and y the wide of the rectangle
P=2(x+y)
A=xy
k=x-y >=0
As (x+y)²-4xy=(x-y)²: A²-4P=k² or P=(A²-k²)/4
In primus, you will find a graph (abacus) giving P for a A and k given.
Negative Area or P are excluded.(just remind the first quadrant, A>=0 and P>=0)
For a given perimeter (P) there are an infinity of Area (A)
Let's say x the length, and y the wide of the rectangle
P=2(x+y)
A=xy
k=x-y >=0
As (x+y)²-4xy=(x-y)²: A²-4P=k² or P=(A²-k²)/4
In primus, you will find a graph (abacus) giving P for a A and k given.
Negative Area or P are excluded.(just remind the first quadrant, A>=0 and P>=0)
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Answer: C. n = 4r + 50
Step-by-step explanation:
The equation is in the form: y =mx + c
y is the number of flowers used.
x is the row number.
Solving for m. Pick any two points. (1, 54) and (2, 58)
m = (Y₂ - Y₁) / (X₂ - X₁)
= (58 - 54) / (2 - 1)
= 4
Solving for c. Use a point to fill up the formula and find c; (1, 54)
y = mx + c
54 = 4 * 1 + c
c = 54 - 4
c = 50
Formula will therefore be;
y = 4x + 50
or;
n = 4r + 50
