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Zinaida [17]
3 years ago
14

Which ordered pairs are solutions to the equation?

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
3 0
Hello,

Answer B

if x=10 then y=10-4=6
if x=5 then y=5-4=1


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Help me with my homework​
Kay [80]

Answer:

a.\frac{x+10}{5} = 9.5

b. $37.50

Step-by-step explanation:

To find out how much the 5 were paying in total, we can add the bill and the tip. This gives us x + 10. Since there are 5 people and they are splitting the bill equally, the total amount would be divided by 5 to get the amount each person pays: \frac{x+10}{5}. We already know the amount they each paid, as it is given as $9.50. Both expressions represent the same thing, do we can set them equal to each other:

9.5 = \frac{x+10}{5}

Now, we can solve.

First, we can multiply by 5 on both sides to get:

47.5 = x + 10

And then subtract 10:

x = 37.5

This means the bill before the tip was $37.50

4 0
3 years ago
21-2(10-3squared)+4=
OleMash [197]
The answer is -1975. Hope I was able to help

6 0
3 years ago
Read 2 more answers
Martin burns 360 calories running for 30 minutes. Paul burns 165 calories for every 15 minute he runs. If Kara runs for 20 minut
Yanka [14]

Answer:  She would have to burn between 220 and 240 calories per minute to have a calorie burn rate between those of Martin and Paul.

Step-by-step explanation:

Martin:

360 calories / 30 min = 12 calories/min

Paul:

165 calories / 15 min = 11 calories/min

Kara:

Needs to burn between 11 and 12 calories/min, so we'll calculate the range:

11 calories/min x 20 min = 220 calories (minimum # calories she can burn)

12 calories/min x 20 min = 240 calories (maximum # calories she can burn)

7 0
3 years ago
On Monday the temperature was -5°F. How many degrees below zero was the temperature
stira [4]
The temperature was 5 degrees below 0
7 0
3 years ago
A ball of radius 15 has a round hole of radius 5 drilled through its center. Find the volume of the resulting solid. Hint: The u
OverLord2011 [107]

Answer:

The volume of the ball with the drilled hole is:

\displaystyle\frac{8000\pi\sqrt{2}}{3}

Step-by-step explanation:

See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

x^2+y^2=15^2\to y=\sqrt{225-x^2}

Then we set the integral for the volume by using shell method:

\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx

That can be solved by substitution:

u=225-x^2\to du=-2xdx

The limits of integration also change:

For x=5: u=225-5^2=200

For x=15: u=225-15^2=0

So the integral becomes:

\displaystyle -\int_{200}^{0}\pi \sqrt{u}du

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

\displaystyle \int_{0}^{200}\pi u^{1/2}du

Then applying the basic rule we get:

\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}

Since that is just half of the solid, we multiply by 2 to get the complete volume:

\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}

=\displaystyle\frac{8000\pi\sqrt{2}}{3}

5 0
4 years ago
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