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kodGreya [7K]
3 years ago
11

A customer purchases a pair of jeans and a few shirts. Each shirt costs the same amount. The expression 60 + 20x represents the

cost before tax. What do the different parts of the expression model? Drag the parts of the expression into the boxes to match each description.
Cost of jeans=
total cost of the shirts=

(I think that 60 represents the price for the jeans and 20x represents the shirts)

Mathematics
2 answers:
myrzilka [38]3 years ago
6 0

thats is the answer

Alexeev081 [22]3 years ago
5 0

Cost before tax = 60 + 20x.

In this model, 60 is used only one time and so, it would represent the pair of jeans.

20x = 20 + 20 + 20 +.... x times

Since, it is given that each shirt costs the same amount, it is clear that 20 represents the cost of one shirt and x represents the number of shirts the customer purchases.

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A Rectangle with sides 100m and 50m. Person B and Person A start walking in the opposite direction at the same point with veloci
Maurinko [17]

Answer:

It takes takes them 31.67 secs to meet after Person A starts walking

OR

34.67 secs after Person B starts walking

Step-by-step explanation:

First, we will find the perimeter of the rectangle

From,

Perimeter of rectangle = 2 (l + b)

Where l is the length

and b is the breadth

From the question, l = 100m

and b = 50m

Hence,

Perimeter of the rectangle = 2 (100+50)

= 2(150) = 300m

Hence, the perimeter of the rectangle is 300m

This is the total distance that will be covered by both persons by the time they meet.

Let the distance covered by person A be S_{1}

and the distance covered by person B be S_{2}

We can write that

S_{1} + S_{2} = 300m

Velocity of person A, V_{A} = 4 m/s

and velocity of person B, V_{B} = 5 m/s

From the question, Person A starts walking 3 seconds after person B,

This means, if person A spends t secs before they meet, then person B would spend (3 + t) secs.

For Person A,

Velocity = 4 m/s

Time = t secs

Distance = S_{1}

From,

Velocity = \frac{Distance}{Time}

Then,

Distance = Velocity \times time

S_{1} = 4 \times t

S_{1} = 4t ...... (1)

For Person B

Velocity = 5 m/s

Time = (t + 3) secs

Distance = S_{2}

Also, from

Distance = Velocity \times time

S_{2} = 5 \times (3+t)

S_{2} = 5(3+t) ...... (2)

Recall that, S_{1} + S_{2} = 300m

Then, S_{2} = 300m - S_{1}

We can then write that,

300m - S_{1} = 5(3+t)

Then,

S_{1} = 300 - 5(3+t) ..... (3)

Equating equations (1) and (3), we get

300 - 5(3+t) = 4t

300 - 15 -5t = 4t\\9t = 285\\t = \frac{285}{9}\\

t = 31.67 secs

This is the time spent by Person A

Hence, it takes takes them 31.67 secs to meet after Person A starts walking OR

34.67 secs after Person B starts walking

3 0
3 years ago
The lines graphed below are perpendicular. The slope of the red line is -2.
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Answer:

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Put the values in above formula we get

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This is the time required by Machine B to create a widget.

8 0
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