Answer: The probability in (b) has higher probability than the probability in (a).
Explanation:
Since we're computing for the probability of the sample mean, we consider the z-score and the standard deviation of the sampling distribution. Recall that the standard deviation of the sampling distribution approximately the quotient of the population standard deviation and the square root of the sample size.
So, if the sample size higher, the standard deviation of the sampling distribution is lower. Since the sample size in (b) is higher, the standard deviation of the sampling distribution in (b) is lower.
Moreover, since the mean of the sampling distribution is the same as the population mean, the lower the standard deviation, the wider the range of z-scores. Because the standard deviation in (b) is lower, it has a wider range of z-scores.
Note that in a normal distribution, if the probability has wider range of z-scores, it has a higher probability. Therefore, the probability in (b) has higher probability than the probability in (a) because it has wider range of z-scores than the probability in (a).
Answer:
34
Step-by-step explanation:
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You just subtract them
113,998-97,813=16,185
Answer:
(0.1392,0.1466)
Step-by-step explanation:
Given that a survey given to consumers leaving a supermarket three days before Thanksgiving asked whether turkey would be part of the Thanksgiving meal
People surveyed = 182
claimed not eating turkey = 26
Sample proportion = 
Std error =
Margin of error = 1.96*SE=
Confidence interval = 