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Sedaia [141]
2 years ago
6

What is the Pythagorean triple generator and how does it work?​

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
7 0

Answer:

Step-by-step explanation:

The Pythagorean Theorem states that

a^2+b^2=c^2

or that the two legs added together squared equal the hypotenuse squared

not: this only works with right triangles

Now Pythagorean triples are the set of sides that follow that rule

an example would be 3,4,5

why is it a Pythagorean triple?

well because it follows

a^2+b^2=c^2

3^2=9\\4^2=16\\16+9=25\\5^2=25

25=25

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B. Solve the following Polynomials:<br>1. u³ + 64​
Art [367]

Answer:

(4 + u)(16 – 4u + u2)

Step-by-step explanation:

64 + u3.

= 43 + u3.

= (4 + u)(42 – 4.u + u2).

= (4 + u)(16 – 4u + u2).

3 0
3 years ago
14 ft<br> 3 ft<br> 6 ft<br> O 87<br> 1313<br> 252ft<br> 0 262<br> 52.31
nikitadnepr [17]

Answer:

35

Step-by-step explanation:

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3 years ago
Please Help I Don't Undertand.
frozen [14]

If triangles AMN and ABC are similar, then

AM/AB = AN/AC

or

AM/(AM + MB) = AN/(AN + NC)

Check if this is true:

AM/AB = 21/(21 + 9) = 21/30 = 7/10

AN/AC = 14/(14 + 6) = 14/20 = 7/10

The angle at vertex A is common to both of the triangles.

Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.

4 0
1 year ago
Write out the first few terms of the series Summation from n equals 0 to infinity (StartFraction 2 Over 3 Superscript n EndFract
anyanavicka [17]

Answer:

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = 15/8

Step-by-step explanation:

The sum you are trying to understand is this.

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n}

Remember that in general when you have a geometric series  

\sum\limits_{n = 0}^{\infty} a*r^n you have that

\sum\limits_{n = 0}^{\infty} a*r^n = \frac{a}{1-r}      and that equality is true as long as     |r| < 1.

Therefore here we have

\sum\limits_{n=0}^{\infty} \frac{2}{3^n}\frac{(-1)^n}{5^n} = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{3*5} \big)^n = \sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n        and   \big|\frac{-1}{15} \big| = \frac{1}{15} < 1

Therefore we can use the formula and

\sum\limits_{n=0}^{\infty} 2* \big(\frac{-1}{15} \big)^n =  \frac{2}{1-(-1/15)} = \frac{2}{1+1/15} = 30/16  = 15/8

5 0
2 years ago
Lines that are tangent to a circle are
jonny [76]

Step-by-step explanation:

Lines that are tangent to a circle are perpendicular to the radius of the circle.

Lines that are tangent to a circle are congruent

5 0
3 years ago
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