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sergiy2304 [10]

3 years ago

6

Suppose the population of a small country is 875,000 and growing at an annual rate of 3%. Identify the rate as either a growth r

ate or decay rate.
a. Decay rate = 3%

b. Growth rate = 3%

1 answer:

just olya [345]3 years ago

8 0

Answer:

Need to calculate 3% of 875 000 which is equal 26250

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Radical 8 plus radical 18

maxonik [38]

Answer:

5√2

Step-by-step explanation:

√8 + √18

We first have to find what is the largest perfect square that goes into √8:

4 is the largest, so therefore → √8 gives you 2√2:

Work: √4 * √2 → 2 * √2 → 2√2

Now we have to find what is the largest perfect square that goes into √18:

9 is the largest, so therefore → √18 gives you 3√2:

Work: √9 * √2 → 3 * √2 → 3√2

Because 2√2 and 3√2 have the same "base" of √2, they can be added together:

2√2 + 3√2 = 5√2 (The "bases" are to be left alone!)

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=if%20%5C%3A%20%28%20%5Cfrac%7B3%7D%7B4%7D%20%29%5E%7B6%7D%20%20%5Ctimes%20%28%20%5Cfrac%7B16%7

zhenek [66]

Answer:

2

Step-by-step explanation:

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{x+2}$

$\frac{3^6}{4^6} \cdot \frac{16^5}{9^5}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{4^6} \cdot \frac{(4^2)^5}{(3^2)^5}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{4^6} \cdot \frac{4^{10}}{3^{10}}=\frac{4^{x+2}}{3^{x+2}}$

$\frac{3^6}{3^{10}} \cdot \frac{4^{10}}{4^6}=\frac{4^{x+2}}{3^{x+2}}$

$3^{-4} \cdot 4^{4}=4^{x+2}3^{-(x+2)}$

This implies

x+2=4

and

-(x+2)=-4.

x+2=4 implies x=2 since subtract 2 on both sides gives us x=2.

Solving -(x+2)=-4 should give us the same value.

Multiply both sides by -1:

x+2=4

It is the same equation as the other.

You will get x=2 either way.

Let's check:

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{2+2}$

$(\frac{3}{4})^6 \times (\frac{16}{9})^5=(\frac{4}{3})^{4}$

Put both sides into your calculator and see if you get the same thing on both sides:

Left hand side gives 256/81.

Right hand side gives 256/81.

Both side are indeed the same for x=2.

4 0

3 years ago

In a research laboratory, a scientist measures the mass of a 1-carat diamond and finds it to be 200 milligrams, measured to the

vlada-n [284]

Answer:

$D=3.5\ gr/cm^3$

Step-by-step explanation:

<u>Density</u>

The density of an object of mass m and volume V is given by

$\displaystyle D=\frac{m}{V}$

It can be expressed in common units like $gr/lt, Kg/m^3, gr/cm^3$ or any other combination of proper mass [M] by volume [V] units.

The data provided in the question is

$m=200\ mg = 0.2\ gr$

$V=0.057\ cm^3$

Thus, the measured density is

$\displaystyle D=\frac{0.2\ gr}{0.057 \ cm^3}$

$\boxed{D=3.5\ gr/cm^3}$

We have expressed the result with 1 decimal place because the mass was measured to the nearest hundred milligrams (or one-tenth grams). Any further decimal is senseless because that precision comes from calculations, not from measurements.

6 0

3 years ago

Solve the inequality 4t^2 ≤ 9t-2 please show steps and interval notation. thank you!

FromTheMoon [43]

Answer: $t\in [\dfrac{1}{4},2]$

Step-by-step explanation:

Given

Inequality is $4t^2\leq9t-2$

Taking variables one side

$\Rightarrow 4t^2-9t+2\leq0\\\Rightarrow 4t^2-8t-t+2\leq0\\\Rightarrow 4t(t-2)-1(t-2)\leq0\\\Rightarrow (4t-1)(t-2)\leq0$

Using wavy curve method

$t\in [\dfrac{1}{4},2]$

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B9%7Dx%20-%20%5Cfrac%7B1%7D%7B3%7D%20%3D%20-1" id="TexFormula1" title="\frac{2

egoroff_w [7]

$\large \mathfrak{Solution : }$

let's solve for x :

$\dfrac{2}{9} x - \dfrac{1}{3} = - 1$

$\dfrac{2}{9} x = - 1 + \dfrac{1}{3}$

$\dfrac{2}{9} x = \dfrac{ - 3 + 1}{3}$

$x = \dfrac{ - 2}{3} \times \dfrac{9}{2}$

$x = - 3$

I hope it helped...

7 0

3 years ago

Read 2 more answers