Answer:
7/48,0.5,9/16,0.75
Step-by-step explanation:
Hope this helps
Answer:
360 mi/h
Step-by-step explanation:
The speed for the outbound trip was ...
speed = distance/time = (715 mi)/(2 1/6 h) = 330 mi/h
The inbound speed was ...
(715 mi)/(1 5/6 h) = 390 mi/h
The airspeed of the plane is the average of these two ground speeds, so is ...
(330 +390)/2 = 360 . . . . mi/h
Answer:
Final amount of customers =30141.44
Step-by-step explanation:
Amount of customer remaining
A= p(1-r/n)^(nt)
P= initial amount of customers
R= rate but it's a negative rate
N= number of times
T= number of years
A= final amount of customers
A= p(1-r/n)^(nt)
A= 51200(1-0.038/14)^(14*14)
A= 51200(1-0.0027)^196
A= 51200(0.9973)^196
A= 51200(0.5887)
A= 30141.44
Answer: The answers for both (a) and (b) is YES.
Step-by-step explanation: A polynomial is an algebraic expression containing two or more algebraic terms, i.e., the sum of several terms that contain different powers of the same variable or variables with real coefficients.
For example, p(x) = 4x²+x+2 is a polynomial in variable 'x'.
(a) Yes, the sum of two polynomials is again a polynomial. For example,
if p(x) = ax² + bx + c and q(x) = dx² + ex + f, where, a, b, c, d, e and f are real numbers, then their sum will be
p(x) + q(x) = (a+d)x²+(b+e)x+(c+f), which is again a polynomial in 'x' with real coefficients.
(b) Yes, the difference of two polynomials is again a polynomial. For example,
p(x) - q(x) = (a-d)x²+(b-e)x+(c-f), which is again a polynomial in 'x' with real coefficients.
Thus, the answer is YES.
