Solve the inequality |6x + 2| < 10 and graph its solution.

1 answer:

8 0

This is a modulus inequality.
First part: when (6x + 2) is positive
6x + 2 < 10
6x < 10 - 2
6x < 8
x < 8/6
x < 4/3

Second part: when (6x + 2) is negative.

-(6x + 2) < 10   Divide both sides of inequality by -1 and change the sign.

(6x + 2) > -10
   6x + 2 > -10
   6x > -10 - 2
   6x > -12 Divide both sides by 6.
   x > -12/6
   x > -2.

Combined solution:   x < 4/3 and x > -2

-2 < x < 4/3.

Graph is a line on the number line between -2 and 4/3.

-2 and 4/3 are excluded from solution.

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A rectangular pool has dimensions of 40 ft. and 60 ft. The pool has a patio area around it that is the same width on all sides.I

ladessa [460]

Area of pool edge = Area of big rectangle - Area of the pool

Area of pool edge = Area of the pool = 40 × 60 = 2400 ft²

2400 = Area of big rectangle - 2400
Area of big rectangle = 2400 + 2400
Area of big rectangle = 4800

Length × width = 4800

From the diagram, we need the length to be [x + x] more than the length of the pool, where x is the distance from the pool edge to the patio edge.

We also need the width of the big rectangle to be [[x + x] more than the width of the pool.

Length = 60 + 2x
Width = 40 + 2x

Length × Width = [60+2x] × [40+2x]
4800 = 2400 + 120x + 80x + 4x²
0 = 4x² + 200x - 2400
0 = 4[x² + 50x - 600]
0 = x² + 50x - 600
0 = [x - 60] [x + 10]

x - 60 = 0 OR x + 10 = 0
x = 60 OR x = -10

We can only use the positive value of x since the context is length

Hence, x = 60