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photoshop1234 [79]
3 years ago
9

2 x 10^5 standard notation

Mathematics
2 answers:
Delicious77 [7]3 years ago
7 0

Answer:

200,000

Step-by-step explanation:

Following the mathematic PEMDAS rule (Parentheses, Exponents, Multiplication, Division, Subtraction) a rule where it gives the order in an algebraic expression/equation shall be completed. in this case, exponents first which equals 100,000 and that times 2 is doubled to 200,000.

Reil [10]3 years ago
3 0

Answer:

2x100000

Step-by-step explanation:

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3 years ago
Let |u| = 10 at an angle of 45° and |v| = 13 at an angle of 150°, and w = u + v. What is the magnitude and direction angle of w?
mixer [17]

Given:

|u|=10 at an angle of 45°.

|v|=13 at an angle of 150°.

w=u+v

To find:

Magnitude and direction angle of w.

Solution:

We have,

w=u+v

\theta = 45^\circ, \phi = 150^\circ

Now,

u_x=|u|\cos \theta=10\cos 45^\circ=7.071

u_y=|u|\sin \theta=u_y=10\sin 45^\circ=7.071

v_x=|v|\cos \phi=13\cos 150^\circ=-11.25833

v_y=|v|\sin \phi=u_y=13\sin 150^\circ=6.5

Using these information, we get

R_x=u_x+v_x=7.071-11.25833=-4.18733

R_y=u_y+v_y=7.071+6.5=13.571

\text{Direction angle}=\tan^{-1}(\dfrac{R_y}{R_x})

\text{Direction angle}=\tan^{-1}(\dfrac{13.571}{-4.18733})

\text{Direction angle}=-72.8239

\text{Direction angle}=107.1476

\text{Direction angle}\approx 107.1

Now,

|w|=\sqrt{(|u|\cos \theta +|v|\cos \phi)^2+(|u|\sin \theta +|v|\sin \phi)^2}

|w|=\sqrt{(10\cos(45)+13\cos 150)^2+(10\sin(45)+13\sin 150)^2}

|w|=\sqrt{(10(\dfrac{1}{\sqrt{2}})+13(-\dfrac{\sqrt{3}}{2}))^2+(10(\dfrac{1}{\sqrt{2}})+13(\dfrac{1}{2}))^2}

|w|=14.20236

|w|\approx 14.20236

Therefore, the correct option is D.

4 0
3 years ago
Read 2 more answers
Identify the shape of the​ distribution, and​ (b) determine the​ five-number summary. Assume that each number in the​ five-numbe
Marat540 [252]

1. The shape of the distribution is: B. skewed left.

2. he five-number summary is: 0, 14, 17, 18, 20.

<h3>What is Left-skewed Distribution?</h3>

If the data distribution that is represented by a box plot is left-skew (negatively skewed), the median will appear closer to the third quartile (Q3) of the box plot. The median is at the point where a vertical line divides the box into two.

Part 1: The box plot shows that the median is close to the third quartile, therefore, the shape of the distribution is described as: B. skewed left.

Part 2: The five-number summary include:

Min. value = 0

Q1 = 14

Median = 17

Q3 = 18

Max. value = 20.

Learn more about left-skewed distribution on:

brainly.com/question/15759915

#SPJ1

4 0
2 years ago
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