Answer : 0.0129
Step-by-step explanation:
Given : Based on FAA estimates the average age of the fleets of the 10 largest U.S. commercial passenger carriers is years and standard deviation is years.
Sample size :
Let X be the random variable that represents the age of fleets.
We assume that the ages of the fleets of the 10 largest U.S. commercial passenger carriers are normally distributed.
For z-score,
For x=14
By using the standard normal distribution table , the probability that the average age of these 40 airplanes is at least 14 years old will be :-
Hence, the required probability = 0.0129
Answer:
C. She makes $127.50 a week
Step-by-step explanation:
Since we are looking for how much she makes every week, we need to multiply her number of hours by the pay. She makes 8.50 per hour and works 15 hours.
8.5x15=127.5
She makes $127.50 a week
Answer:
32.975
Step-by-step explanation:
Answer:
Yes, we reject the auto maker's claim.
Step-by-step explanation:
H0 : μ ≥ 20
H1 : μ < 20
Sample mean, xbar = 18 ;
Sample size, n = 36
Standard deviation, s = 5
At α = 0.01
The test statistic :
(xbar - μ) ÷ s /sqrt(n)
(18 - 20) ÷ 5/sqrt(36)
-2 /0.8333333
= - 2.4
Pvalue from test statistic : Pvalue = 0.00819
Pvalue < α
0.00819 < 0.01
Hence, we reject the Null
X = smallest angle, y = middle angle, z = largest angle
x + y + z = 180...interior angles of a triangle add up to 180 degrees
y = 1/2z.....z = 2y
y = 3x.......1/3y = x
1/3y + y + 2y = 180....multiply everything by 3
y + 3y + 6y = 540
10y = 540
y = 540/10
y = 54 <== the middle angle
z = 2y
z = 2(54)
z = 108 <=== largest angle
1/3y = x
1/3(54) = x
54/3 = x
18 = x <=== smallest angle