1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nikklg [1K]
3 years ago
5

Select the correct answer from the drop-down menu consider circle C with diameter DE

Mathematics
1 answer:
alexgriva [62]3 years ago
7 0

Answer:

ok

Step-by-step explanation:

You might be interested in
Heptagon octagon nonagon
Elodia [21]
The answer would for the problem would be 13
7 0
3 years ago
What is the midpoint of this point (-4,2) and (8,0)? ​
marissa [1.9K]

Answer:

Mid - point = ( 2 , 1 )

Step-by-step explanation:

Let A = ( - 4 , 2 ) and B = ( 8 , 0 )

Let P = ( x , y ) be the mid-point of AB

Then,

     P = (\frac{x_A + x_B}{2} , \frac{y_A + y_B}{2} ) \\\\P =(\frac{-4+8}{2} , \frac{2+0}{2}) \\\\P = ( \frac{4}{2} , \frac{2}{2} )\\\\P = ( 2 , 1)

6 0
3 years ago
Read 2 more answers
Find the absolute maximum and minimum values of f on the set D. f(x,y)=2x^3+y^4, D={(x,y) | x^2+y^2<=1}.
castortr0y [4]

Answer:

absolute maximum is f(1, 0) = 2 and the absolute minimum is f(−1, 0) = −2.

Step-by-step explanation:

We compute,

$ f_x = 6x^2, f_y=4y^3 $

Hence, $ f_x = f_y = 0 $  if and only if (x,y) = (0,0)

This is unique critical point of D. The boundary equation is given by

$ x^2+y^2=1$

Hence, the top half of the boundary is,

$ T = \{ x, \sqrt{1-x^2} : -1 \leq x \leq 1\}

On T we have, $ f(x, \sqrt{1-x^2} = 2x^3 +(1-x^2)^2 = x^4 +2x^3-2x^2+1  \text{ for}\ -1 \leq x \leq 1$

We compute

$ \frac{d}{dx}(f(x, \sqrt{1-x^2}))= 4x^3+6x^2-4x = 2x(2x^2+3x-2)=2x(2x-1)(x+2)=0$

0 if and  only if x=0, x= 1/2 or x = -2.

We disregard  $ x = -2 \notin [-1,1]$

Hence, the critical points on T are (0,1) and $(\frac{1}{2}, \sqrt{1-(\frac{1}{2})^2}=\frac{\sqrt3}{2})$

On the bottom half, B, we have

$ f(x, \sqrt{1-x^2})= f(x,-\sqrt{1-x^2})$

Therefore, the critical points on B are (0,-1) and $( 1/2, -\sqrt3/2)  

It remains to  evaluate f(x, y) at the points $ (0,0), (0 \pm1), (1/2, \pm \sqrt3/2) \text{ and}\  (\pm1, 0)$ .

We should consider  latter two points, $(\pm1,0)$, since they are the boundary points for the T and also  B. We compute $ f(0,0)=0, \ \f(0 \pm1)=1, \ \ f(0, \pm \sqrt3/2)=9/16, \ \ f(1,0 )= 2 \text{ and}\ \ f(-1,0)= -2 $

We conclude that the  absolute maximum = f(1, 0) = 2

And the absolute minimum = f(−1, 0) = −2.

6 0
3 years ago
A 12​-foot piece of string is cut into two pieces so that the longer piece is 3 feet longer than twice the shorter piece. Find t
nikklg [1K]
Hope this helps you.

5 0
4 years ago
Allan borrowed $5500 from his father to buy a car. He repaid him after 11 months with interest of 8%. Find the total amount he r
NARA [144]
I need to know the interest of 8% is monthly or yearly interest to find out the answer.
4 0
3 years ago
Other questions:
  • Write equation of the line containing (-3,4) and (-1,-2)
    15·1 answer
  • Graph the inequality on a number line K> 1
    11·1 answer
  • What’s the number?!!!!!!
    7·1 answer
  • Carys earns 10 dollars an hour. How many hours would it take to earn $1?
    9·2 answers
  • a garden has the shape of a right triangle with one leg 6 meters longer than the other. the hypotenuse is 6 meters less than twi
    10·1 answer
  • what is barbara has had a checking account for four months. The number of Barbara's debit card transactions appear in the table
    8·1 answer
  • I’ll give out genius is someone can help me create a story about a graph pictured below!!
    10·2 answers
  • Find the Circumference of The Circle with Radius 3.5cm​
    15·2 answers
  • Please help me in this:
    13·1 answer
  • Which of the following equations is equivalent to x^2 - 8x = 16?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!