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Alexxx [7]
3 years ago
13

How do you solve this?

Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0
I hope this is the answer:)
3x-x+2=4
sorry... this answer is VERY wrong



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Using the total cost for Ashley's phone plan in the previous question, Calculate the total cost if she talked for 500 minutes an
andreyandreev [35.5K]
What was the total cost
6 0
3 years ago
Jenna sells apples and pears. If 20 apples and 60 pears re sold every hour, there will be 80 pears when all the apples are sold.
lutik1710 [3]

Answer:

There are 1,360 pears.

Step-by-step explanation:

Suppose that there are P pears and A apples.

We know that:

"If 20 apples and 60 pears are sold every hour, there will be 80 pears when all the apples are sold."

Suppose that all of these are sold after N hours, then:

20*N = A

80*N = P - 80

We also know that:

"if 60 apples and 20 pears are sold every hour, there will be 400 pears when all the apples are sold."

60*N = A

20*N = P - 400

Then we have four equations:

20*N = A

80*N = P - 80

60*N = A

20*N = P - 400

From the first one and the second one, we get:

20*N = A = 20*N = P - 400

A = P - 400

Now we have 3 equations:

80*N = P - 80

60*N = A

A = P - 400

Now we can just replace the third equation into the second one, then we get:

60*N = A = P - 400

Now we have two equations:

80*N = P - 80

60*N = P - 400

Now, remember that we want to find the number of pears, so we want to find the value of P.

To do it, we can take the quotient of the two equations, so we get:

(80*N)/(60*N) = (P - 80)/(P - 400)

8/6 = (P - 80)/(P - 400)

Now we can solve this for P

(8/6)*(P - 400) = P - 80

(8/6)*P - (8/6)*400 = P - 80

(8/6)*P - P = (8/6)*400 - 80

(2/6)*P = (8/6)*400 - 80

P = (6/2)*( (8/6)*400 - 80 )

P = 3*( (8/6)*400 - 80 ) = 1,360

There are 1,360 pears.

3 0
2 years ago
1/3x=5/12 show your work
insens350 [35]

Answer:

4/5 or 0.8

Step-by-step explanation:

1/3x = 5/12

<em>cross</em><em> </em><em>multiply</em>

(12×1) = (5×3x)

<em>divide</em><em> </em><em>through</em> <em>by</em> <em>1</em><em>5</em>

x = 12/15

x = 4/5 <em>o</em><em>r</em><em> </em>0.8

3 0
3 years ago
In an examination 80% students passed. if 15 less have appeared and 10 less have passed, the ratio of passers to failures would
Nina [5.8K]

Answer:

60 students passed, and 75 appeared in examination.

Step-by-step explanation:

Let's say s is the total number of students and p is the number of students who passed.

80% of the students passed, so:

0.8 s = p

If there were 10 less passers, and 15 less students (5 less failures), then the ratio of passers to failures would be 5/1.

(p − 10) / (s − p − 5) = 5 / 1

Simplify the second equation:

p − 10 = 5 (s − p − 5)

p − 10 = 5s − 5p − 25

6p = 5s − 15

Substitute the first equation.

6 (0.8 s) = 5s − 15

4.8 s = 5s − 15

0.2 s = 15

s = 75

p = 0.8 s

p = 60

60 students passed, and 75 appeared in examination.

5 0
3 years ago
Y=2x+5 y=3x−1 solve by subsitution
loris [4]

Answer:

(6,17)

Step-by-step explanation:

2x+5=3x-1

-3x        -3x

-x+5=-1

-5      -5

-x=-6

^divided by -1 on both sides

x=6

y=2x+5

y=(2)(6)+5

y=17

5 0
2 years ago
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