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My name is Ann [436]
3 years ago
11

A fisherman can row upstream at 4 mph and downstream at 6 mph. He started rowing upstream until he got tired and then rowed down

stream to his starting point. How far did the fisherman row if the entire trip took 2 ​hours?
Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

A fisherman can row upstream at 4 mph and downstream at 6 mph. He started rowing upstream until he got tired and then rowed downstream to his starting point. The distance of how far the fisherman row if the entire trip took 2 hours is  9.6 miles

<u />

The speed of an object refers to the change of the object's distance within a specified time.

Mathematically, we can have;

\mathbf{Speed =\dfrac{distance}{time}}

Distance = speed × time

From the information given;

  • The fisherman row upstream for 4 miles/ hour.
  • The distance covered by the fisherman = 4 × t₁  ----- (1)

  • The fisherman row downstream at 6 miles/ hour
  • The distance covered by the fisherman = 6 × t₂  ------ (2)

  • SInce it took the entire trip 2 hours, we can infer that:

  • t₁ + t₂ = 2
  • t₂ = 2 - t₁

From equation (2), replace the above value of t₂ into equation (2)

  • d = 6 t₂
  • d = 6(2 - t₁)
  • d = 12 - 6t₁

From equation (1)

  • d = 4 t₁  

Equation both distance together, we have:

  • 12 - 6t₁ = 4t₁
  • 12 = 4t₁ + 6t₁
  • 12 = 10t₁
  • t₁ = 12/10
  • t₁ = 1.2  hours

From t₂ = 2 - t₁

  • t₂ = 2 - 1.2
  • t₂ = 0.8 hours

From d = 4t₁

Replace t₁ with 1.2 hours

  • d = 4(1.2 hours)
  • d = 4.8 miles

Also, from d = 6t₂

  • d = 6(0.8)
  • d = 4.8 miles

Therefore, we can conclude that the distance of how far the fisherman row if the entire trip took 2 hours is (4.8+4.8) miles = 9.6 miles

Learn more about distance here:

brainly.com/question/12319416?referrer=searchResults

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7 0
3 years ago
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Your friend asks if you would like to play a game of chance that uses a deck of cards and costs $1 to play. They say that if you
gtnhenbr [62]

Answer:

Expected value = 40/26 = 1.54 approximately

The player expects to win on average about $1.54 per game.

The positive expected value means it's a good idea to play the game.

============================================================

Further Explanation:

Let's label the three scenarios like so

  • scenario A: selecting a black card
  • scenario B: selecting a red card that is less than 5
  • scenario C: selecting anything that doesn't fit with the previous scenarios

The probability of scenario A happening is 1/2 because half the cards are black. Or you can notice that there are 26 black cards (13 spade + 13 club) out of 52 total, so 26/52 = 1/2. The net pay off for scenario A is 2-1 = 1 dollar because we have to account for the price to play the game.

-----------------

Now onto scenario B.

The cards that are less than five are: {A, 2, 3, 4}. I'm considering aces to be smaller than 2. There are 2 sets of these values to account for the two red suits (hearts and diamonds), meaning there are 4*2 = 8 such cards out of 52 total. Then note that 8/52 = 2/13. The probability of winning $10 is 2/13. Though the net pay off here is 10-1 = 9 dollars to account for the cost to play the game.

So far the fractions we found for scenarios A and B were: 1/2 and 2/13

Let's get each fraction to the same denominator

  • 1/2 = 13/26
  • 2/13 = 4/26

Then add them up

13/26 + 4/26 = 17/26

Next, subtract the value from 1

1 - (17/26) = 26/26 - 17/26 = 9/26

The fraction 9/26 represents the chances of getting anything other than scenario A or scenario B. The net pay off here is -1 to indicate you lose one dollar.

-----------------------------------

Here's a table to organize everything so far

\begin{array}{|c|c|c|}\cline{1-3}\text{Scenario} & \text{Probability} & \text{Net Payoff}\\ \cline{1-3}\text{A} & 1/2 & 1\\ \cline{1-3}\text{B} & 2/13 & 9\\ \cline{1-3}\text{C} & 9/26 & -1\\ \cline{1-3}\end{array}

What we do from here is multiply each probability with the corresponding net payoff. I'll write the results in the fourth column as shown below

\begin{array}{|c|c|c|c|}\cline{1-4}\text{Scenario} & \text{Probability} & \text{Net Payoff} & \text{Probability * Payoff}\\ \cline{1-4}\text{A} & 1/2 & 1 & 1/2\\ \cline{1-4}\text{B} & 2/13 & 9 & 18/13\\ \cline{1-4}\text{C} & 9/26 & -1 & -9/26\\ \cline{1-4}\end{array}

Then we add up the results of that fourth column to compute the expected value.

(1/2) + (18/13) + (-9/26)

13/26 + 36/26 - 9/26

(13+36-9)/26

40/26

1.538 approximately

This value rounds to 1.54

The expected value for the player is 1.54 which means they expect to win, on average, about $1.54 per game.

Therefore, this game is tilted in favor of the player and it's a good decision to play the game.

If the expected value was negative, then the player would lose money on average and the game wouldn't be a good idea to play (though the card dealer would be happy).

Having an expected value of 0 would indicate a mathematically fair game, as no side gains money nor do they lose money on average.

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2 years ago
How many distinct diagonals of a convex heptagon (7-sided polygon) can be drawn?
valkas [14]

The convex heptagon has 14 distinct diagonals can be drawn

Step-by-step explanation:

A polygon is said to be a heptagon if it has 7 vertices, 7 sides and 7 angles. A heptagon is called a convex heptagon if the lines connecting any two non-adjacent vertices lie completely inside the heptagon

The formula of number of diagonals in any polygon is d=\frac{n(n-3)}{2} , where

  • d is the number of the diagonals of the polygon
  • n is the number of sides of the polygon

∵ The heptagon has 7 sides

∴ n = 7

∵ The number of diagonals = \frac{n(n-3)}{2}

- Substitute n by 7 in the rule above

∴ The number of diagonals = \frac{7(7-3)}{2}

∴ The number of diagonals = \frac{7(4)}{2}

∴ The number of diagonals = \frac{28}{2}

∴ The number of diagonals = 14

The convex heptagon has 14 distinct diagonals can be drawn

Learn more:

You can learn more about the polygons in brainly.com/question/6281564

#LearnwithBrainly

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3 years ago
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lina2011 [118]

Answer:

5

Step-by-step explanation:

Use PEMDAS to complete the problem

PE doesn't matter, there's not parentheses or exponents

MD=Multiplication and Division. Do 3*6=9, now your problem looks like 9-4

AS=Addition and Subtraction. 9-4=5

4 0
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gladu [14]

Hi, there.

For this question, we can apply the Pythagorean theorem a^2 + b^2 = c^2.

I'm sure you've seen this equation before, and they kind of tried to trip you up with this problem. Trust me, it's easier than it looks. Let's break it down.

Lengths a and b both have the value of 48, which means that the value s in \sqrt{2s^2} is 48, because the length of the hypotenuse is the same as the length and height squared multiplied by 2.

Plug in the value for c: a^2 + b^2 = (\sqrt{2s^2})^2

Plug in the value for s:

(\sqrt{2(48^2)})^2

Do the innermost exponents first:

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The square root symbol and the power of 2 cancel each other out, so we are left with:

s = 2(2304), so the hypotenuse is 4608 inches.

4 0
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