Ask question

Ask question

All categories

My name is Ann [436]

2 years ago

11

A fisherman can row upstream at 4 mph and downstream at 6 mph. He started rowing upstream until he got tired and then rowed down

stream to his starting point. How far did the fisherman row if the entire trip took 2 hours?

1 answer:

shepuryov [24]2 years ago

3 0

A fisherman can row upstream at 4 mph and downstream at 6 mph. He started rowing upstream until he got tired and then rowed downstream to his starting point. The distance of how far the fisherman row if the entire trip took 2 hours is 9.6 miles

<u />

The speed of an object refers to the change of the object's distance within a specified time.

Mathematically, we can have;

$\mathbf{Speed =\dfrac{distance}{time}}$

Distance = speed × time

From the information given;

The fisherman row upstream for 4 miles/ hour.
The distance covered by the fisherman = 4 × t₁ ----- (1)

The fisherman row downstream at 6 miles/ hour

The distance covered by the fisherman = 6 × t₂ ------ (2)

SInce it took the entire trip 2 hours, we can infer that:

t₁ + t₂ = 2
t₂ = 2 - t₁

From equation (2), replace the above value of t₂ into equation (2)

d = 6 t₂
d = 6(2 - t₁)
d = 12 - 6t₁

From equation (1)

d = 4 t₁

Equation both distance together, we have:

12 - 6t₁ = 4t₁
12 = 4t₁ + 6t₁
12 = 10t₁
t₁ = 12/10
t₁ = 1.2 hours

From t₂ = 2 - t₁

t₂ = 2 - 1.2
t₂ = 0.8 hours

From d = 4t₁

Replace t₁ with 1.2 hours

d = 4(1.2 hours)
d = 4.8 miles

Also, from d = 6t₂

d = 6(0.8)
d = 4.8 miles

Therefore, we can conclude that the distance of how far the fisherman row if the entire trip took 2 hours is (4.8+4.8) miles = 9.6 miles

Learn more about distance here:

brainly.com/question/12319416?referrer=searchResults

You might be interested in

Two triangles are similar. The perimeter of the smaller one is 16. The ratio of the corresponding sides is 2:5. The sides of the

Eddi Din [679]

Answer:

Perimeter of larger triangle is 40.

Step-by-step explanation:

Given:

Perimeter of smaller circle = 16

Ratio of corresponding side = 2:5

We need to find the perimeter of the larger triangle.

Solution:

Let the perimeter of the larger triangle be 'x'.

Therefore by theorem which states that;

" When a triangle have scale factor a:b then the ratio of the perimeters is a:b".

Here Ratio is 2:5, so we can say by theorem, Ratio of perimeters is 2:5

framing in equation form we get;

$\frac{\textrm{Perimeter of smaller triangle}}{\textrm{Perimeter of Larger triangle}}=\frac{2}{5}$

Substituting the values we get;

$\frac{16}{x}=\frac{2}{5}$

By Cross multiplication we get;

$16\times 5=2x\\\\80=2x$

Dividing both side by 2 we get;

$\frac{80}{2}=\frac{2x}{2}\\\\x=40$

Hence Perimeter of larger triangle is 40.

7 0

3 years ago

Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,

Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁, of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

$Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times (720-576)\times (720 - 672)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times 144 \times 48}$ = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

$Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}$

The semi-perimeter, s₂, of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

$Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times (690 -228)\times (690 - 480)}$

$Area\, of \, \Delta ACD = \sqrt{690 \times 18\times 462\times 210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2$

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0

3 years ago

how many cups of walnuts are needed to make 3.75 batches of muffins? One batch of walnut muffins uses 1.33

Bad White [126]

How many cups of walnuts are needed to make 3.75 batches of muffins? One batch of walnut muffins uses 1.33
1.13x3=3.39

5 0

3 years ago

the ratio of the length to width for a rectangular yard is 3:10. if the width of the yard is 25 feet, what is the length of the

ra1l [238]

Answer:

833.333333333333333333333333333333

Step-by-step explanation:

250*10/3 =

3 0

3 years ago

A couch regularly sells for $840. The sale price is $714. Find the percent decrease of the sale price from the regular price

Rudiy27

15% decrease from regular price

5 0

3 years ago