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zubka84 [21]
3 years ago
14

You want to build a chair that does not rock from side to side when one of the legs is a different length than the others. How

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

I think 3. The other 2 legs can have the same balance as the different leg.

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Help i cant get this wrong
pashok25 [27]

Answer:

D

Step-by-step explanation:

I'm not the greatest in this subject, but I think that it's D/If the roof leaks, then the ceiling gets damaged because it clearly says that in the statement. It could be all of them, though, but this is my answer. Hope it helps!

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4 years ago
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HEEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPP
zheka24 [161]
It is the third bubble
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3 years ago
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Tim Tradesman had a taxable income of $82,500. He figured his tax from the table.
kakasveta [241]
<span>His earned income level are as follows.
 
The base amount is $14,138.50

</span><span><span>The amount over $62,450 = $82,500 - $62,450 =$20,050

The amount of tax on the third $20,050 is given by 31% of $20,050 = 0.31 x $20,050 = $6,215.5</span>
(i.e. Multiply line 3 by 31% = $6,215.5)

Total tax = $ 14,138.50 + $6,215.50 = $20,354
(i.e. Add lines 2 and 4 = $</span>20,354)
8 0
3 years ago
Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
babunello [35]

\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=x^2+y

\dfrac{\partial f}{\partial y}=y^2+x

\dfrac{\partial f}{\partial z}=ze^z

Integrating both sides of the latter equation with respect to z tells us

f(x,y,z)=e^z(z-1)+g(x,y)

and differentiating with respect to x gives

x^2+y=\dfrac{\partial g}{\partial x}

Integrating both sides with respect to x gives

g(x,y)=\dfrac{x^3}3+xy+h(y)

Then

f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)

and differentiating both sides with respect to y gives

y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C

So the scalar potential function is

\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}

By the fundamental theorem of calculus, the work done by \vec F along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it L) in part (a) is

\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}

and \vec F does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them L_1 and L_2) of the given path. Using the fundamental theorem makes this trivial:

\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3

\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

8 0
3 years ago
Select the correct solution set. 50 ≥ 15x
Semenov [28]
The answer (i think) is 3 <span>≥</span> x. hope i helped
7 0
3 years ago
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