The given line passes through the points (-1,-1) and (4.1).

Mathematics

1 answer:

ira [324]3 years ago

6 0

Answer:

(-1,-1) and (4.1).

1+1

slope of the line: m= ------- = 2/5

4+1

the slope of the perpendicular line: -5/2 and point (-1,3)

(y-3) = -5/2(x+1)

You might be interested in

Drag < or > to complete each equation. Use the number lines as needed.

mrs_skeptik [129]

Answer:

7/8 + 7/8 > 2

Step-by-step explanation:

7/8 + 7/8 = 14/8 lr 1 6/8 or 1 3/4

6 0

3 years ago

The equation is ax+r=7 <br><br>how do I solve for r??

Strike441 [17]

The solution is r= 7/a-x How did i do this?
Your equation is ax+ r=7, so the goal is to isolate the r. You begin by dividing the a from the ax. Remember, what you do to one side, you must do to the other. So you do 7/a, since you can't simplify 7/a, leave it as it is. Next, your equation should look like this x+r=7/a. In order to isolate the r, you move the x to the other side by subtracting, which leaves you with the answer of r= 7/a-x.
Hope this helped!

7 0

4 years ago

Read 2 more answers

Prove that: <br>(1 + Tan²A) Cos²A = 1

Artyom0805 [142]

Step-by-step explanation:

=(1+ sin^2 A/cos^2 A).cos^2 A

=[(cos^2 a+sin^2 a)/cos^2 a].cos^2 A

=[1/cos^2 a] . cos^2 a

6 0

3 years ago

Which equation represents a line that passes through 4 6) and is parallel to the line whose equation is 3x - 4y= 6