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photoshop1234 [79]
3 years ago
11

The given line passes through the points (-1,-1) and (4.1).

Mathematics
1 answer:
ira [324]3 years ago
6 0

Answer:

(-1,-1) and (4.1).

                                     1+1

slope of the line: m= ------- = 2/5

                                     4+1

the slope of the perpendicular line:  -5/2  and   point  (-1,3)

(y-3) = -5/2(x+1)

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Area of circle with diameter of 1 m?
Elena-2011 [213]

Answer:

A = 0.785m²

B = 31400cm²

C = 7850cm²

D = 785,000mm²

Step-by-step explanation:

To solve this question, we'll have to find the area of a circle which is

Area of a circle = πr²

1. The diameter of the circle = 1m

Area of a circle = πr²

r = radius of the circle

π = 3.14

Radius = diameter / 2

Radius = 1 / 2 = 0.5m

Area = 3.14 × (0.5)²

Area = 3.14 × 0.25

Area = 0.785m²

2. Radius = 100cm

Area of a circle = πr²

Area = 3.14 × (100)²

Area = 3.14 × 10000

Area = 31400cm²

3. Diameter = 100cm

Area = πr²

Radius = diameter / 2

Radius = 100 / 2

Radius = 50cm

Area = πr²

Area = 3.14 × (50)²

Area = 3.14 × 2500

Area = 7850cm²

4. Radius = 500mm

Area = πr²

Area = 3.14 × (500)²

Area = 3.14 × 250,000

Area = 785,000mm²

7 0
4 years ago
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Charlotte cuts a 3-foot long ribbon into 4 equal pieces to trim a square pillow. How long is each piece of ribbon?
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Answer:0.75

Step-by-step explanation:

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3 years ago
24. The farmer's market has strawberries that sell for $5 per pound and cherries that sell for $3 a pound. Write an
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Answer:

5s+3c=30

Step-by-step explanation:

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The scale factor of a model of a hot air balloon to the actual hot air balloon is 1 to 5. the volume of the actual balloon is 50
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\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\


\bf \cfrac{model}{actual}\qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\implies \cfrac{1}{5}=\cfrac{\sqrt[3]{v}}{\sqrt[3]{5000}}\implies \cfrac{1}{5}=\sqrt[3]{\cfrac{v}{5000}}
\\\\\\
\left( \cfrac{1}{5} \right)^3=\cfrac{v}{5000}\implies \cfrac{1^3}{5^3}=\cfrac{v}{5000}\implies \cfrac{1}{125}=\cfrac{v}{5000}


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3 years ago
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Answer:b

Step-by-step explanation:

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