1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tamiku [17]
3 years ago
6

Draw a triangle that is both a right triangle and an isosceles triangle. You can use either pencil and paper, or a draw program.

2.Label the angles. What are the measurements of the angles that are not equal to 90 degrees? 3.Describe the two sides opposite the angles that are not equal to 90 degrees. 4.Now draw an equilateral triangle. Label the measurements of the angles. Can an equilateral triangle ever be a right triangle too? Explain your answer. 5.Finally, draw a right triangle. Can this triangle ever have an obtuse angle? Explain your answer.
Mathematics
1 answer:
dem82 [27]3 years ago
6 0
2. measurements can be any to complementary angles.
   for example, 60 & 30
3. the 2 sides are equal. Since it is an isosceles triangle.
4.an equi.triangle can never be right angled. Since, all angles are 60° in an             equi.triangle.
5. right triangle can never have an obtuse angle since one angle is already          90°. therefore the other two agles are supposed to be acute angles.[ since        sum of all angles in a triangle is 180°]
You might be interested in
Given the initial inequality −4 (7)<br> c. (−4) = (7)
Katen [24]

Answer:

Step-by-step explanation:

Simplify 4*(7-c)

4

⋅

(

7

−

c

)

4

⋅

(

7

-

c

)

Apply the distributive property.

4

⋅

7

+

4

(

−

c

)

4

⋅

7

+

4

(

-

c

)

Multiply.

Tap for more steps...

Multiply 4

4

by

7

7

.

28

+

4

(

−

c

)

28

+

4

(

-

c

)

Multiply

−

1

-

1

by

4

4

.

28

−

4

c

28

-

4

c

28

−

4

c

6 0
2 years ago
Read 2 more answers
winthrop Middle School had enrollment of 1,342 and a total of 215 teachers. what was the student teacher ratio for this School w
eimsori [14]
Teachers= 215
Students= 1,342

Student: Techer
= 1,342: 215
= 62.1:1
= \frac{62.1}{1}
3 0
2 years ago
Read 2 more answers
Work out<br> (9×10²)+(7×10³)<br> State your answer in standard form
Sunny_sXe [5.5K]

Answer:

(9×10×10)+(7×10×10)

900+700

1600

1.6×10^3

4 0
3 years ago
a shipment of sugar fills 4 1/3 containers. if each container holds 2 1/7 tons of sugar, what is the amount of sugar in the enti
emmasim [6.3K]

To find the answer we need multiply the number of containers by number tons of sugar each container has.

(4 1/3 )*(2 1/7).

To calculate , we need to convert mixed numbers into improper fractions.

4 1/3 = (4*3 +1)/3 = 13/3

2 1/7 = (2*7+1)/7 =15/7

(4 1/3 )*(2 1/7) = (13/3) * (15/7) = (13*5)/7 = 65/7 = 9 2/7 (tons)

Answer: 9 2/7 tons.


8 0
2 years ago
The sum of two numbers is 52. One number is 3 times as large as the other. What are the numbers?
JulsSmile [24]
<span> Let x be the smaller number.
Then 3x is the larger number.
We also know that the smaller added to the larger is 52, or:
x + 3x = 52
4x =52
x = 13
Therefore the smaller is 13, the larger is 3(13)=39. </span>
3 0
3 years ago
Read 2 more answers
Other questions:
  • Does anyone know the answer ?
    15·1 answer
  • Prove ΔPAB is isosceles.
    9·1 answer
  • Deserts advance linearly, in easily mappable patterns.<br><br><br> True <br> False
    13·2 answers
  • Which would the phrase "five more than a number" look like as a variable
    10·1 answer
  • For the expression,use a property to write an equivalent expression. Tell which property you used. 3y+4y=
    6·2 answers
  • PLS HELP, IM DUMB
    11·2 answers
  • Solve the equation please
    11·1 answer
  • What is the greatest common factor of 42 and 15?
    5·2 answers
  • Find the perimeter of the figure. I’ll mark brainliest if correct
    7·2 answers
  • Jerry bought 5 candy bars for $14.75. if the king size candy bar cost $3.75 and a regular size candy bar cost $1.75, how much of
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!