General exponential equation
y = A(1+r)^x
where
A = initial value
r = rate increase (+) or decrease (-)
x = time period of the change
y = projected value
y = 300(1.05)^x
in this problem, x = years after 2017
we want to find an x that makes the value more than or equal to 650
650 <= 300(1.05)^x
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Answer:
Mateo jogged 8 3/20 miles in the past 2 days.
Step-by-step explanation:
Given:-
Distance on Saturday = 3 3/4
Distance on Sunday = 4 2/5
Total distance = 3 3/4 + 4 2/5
= 15/4 + 22/5
= LCM of deniminators (20)
= 75/20 + 88/20
= (75 + 88)/20
= 163/20
= 8 3/20
Im not sure but i think its d
