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mestny [16]
4 years ago
9

How do actresses use math?

Mathematics
1 answer:
ICE Princess25 [194]4 years ago
6 0
Is this a joke? If so, not sure.
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The drama club you are part of is hosting a pancake breakfast. You are in charge of buying the sausage, which costs $5 per pound
antiseptic1488 [7]

Answer:

<h2>C.</h2>

Step-by-step explanation:

Look at the pictures.

x - sausage

y - bacon

A. 20 pounds of sausage and 90 pound of bacon

x = 20 → y = 100 > 90

B. 40 pound of sausage and 40 pound of bacon

x = 40 → y = 75 > 40

C. 60 pound of sausage and 80 pound of bacon

x = 60 → y = 50 < 80

D. 80 pound of sausage and 20 pound of bacon​

x = 80 → y = 25 > 20

4 0
3 years ago
Read 2 more answers
A set of data has 12 pieces of data. Which of the following statements is NOT TRUE?
BARSIC [14]
To help you understand this, it is helpful to create a sample set of data:

__,__,__,(Q1 is here)__,__,__,(median is here)__, __,__,(Q3is here)__,__,__

A. The first 3 lines are 3 pieces of data in the first quartile.

B. here are 6 pieces of data between the 1st and 3rd quartiles.

D. There are 3 pieces of data in the upper quartile.
                                 

5 0
3 years ago
Two parallel Lines are intersected by a transversal
zubka84 [21]

Answer:

27 degrees

Step-by-step explanation:

they have relation with vertical opposite angle

7 0
3 years ago
Please help me with this
My name is Ann [436]

Just do 72 - 9 = 63

Hope this helps

4 0
3 years ago
Read 2 more answers
Given the volume of Figure A is 512cm ^3and Figure B is 343cm^3, find the ratio of the perimeter from Figure A to Figure B.
sp2606 [1]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\[2em] \begin{array}{ccccllll} &\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\ \cline{2-4}&\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}\\\\[-0.35em] ~\dotfill

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{\textit{figure A}}{\textit{figure B}}\qquad \qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{512}}{\sqrt[3]{343}}\qquad \begin{cases} 512=&2^9\\ &2^{3\cdot 3}\\ &(2^3)^3\\ 343=&7^3 \end{cases}\implies \cfrac{s}{s}=\cfrac{\sqrt[3]{(2^3)^3}}{\sqrt[3]{7^3}} \\\\\\ \cfrac{s}{s}=\cfrac{2^3}{7}\implies \cfrac{s}{s}=\cfrac{8}{7}\implies s:s = 8:7\impliedby \textit{ratio of the }\stackrel{sides~and}{perimeters}

5 0
4 years ago
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