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horsena [70]
2 years ago
11

Mr. Marco painted a picture with an area of 2 2/4 square feet. The painting is 2 feet long. What is the perimeter of the paintin

g?
Mathematics
1 answer:
mr_godi [17]2 years ago
7 0
Step 1: Replace the variables with numbers

A=lw
A=2(1.25)
A= 2.5 (Fraction 2 2/4)

Step 2: Use the perimeter formula (P=l+w+l+w or P=(l+w)2)

P=(l+w)2
P=(2+1.25)2
P=(3.25)2
P=6.5

Answer is 6.5 I hope this helped ^^
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How to find variables of these #2 & #3
Lubov Fominskaja [6]
So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles  like  \bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
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\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
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\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}

now.. for 3) will be the second picture below


\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
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\textit{now, because you already know what "x" is, we can use it below}
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\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
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\textit{and let us use "x" again below}
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\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}

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3 years ago
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now, side TV is on both triangles, and is shared by both, so is the same length, so TV on one triangle is equal to TV on the other

check the picture below

so, you have one Angle, another Angle, and then a Side
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