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4 years ago

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A zookeeper predicted the weight of a new baby elephant to be 250 pounds when it was born. The elephant actually weighed 282 pou

nds at birth. What was the percent error of the zookeeper's prediction?

1 answer:

worty [1.4K]4 years ago

3 0

About 11% - I first subtracted 250 from 282, to get 32. I then did 32/282 to get .11.... You round that out to about 11%

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6. To predict the annual rice yield in pounds we use the equation y-hat = 859 + 5.76x1 + 3.82x2 where x1 represents the number o

zysi [14]

The yield is given by the regression equation
y = 859 + 5.76x₁ + 3.82x₂
where
x₁ = number of acres planted
x₂ = number of acres harvested

The goodness of fit is r² = 0.94.
This appears to a very good fit to the data because it is almost equal to 1.
To assess the goodness of fit in a statistical sense, it may also necessary to perform an F-test in a hypothesis test. This is not possible without having raw measured data.
For this problem, r²=0.94 may be considered to be a very good fit to the measured data.

Part a.
When x₁ = 3200 acres and x₂ = 3000 acres, obtain
y = 859 + 5.76*3200 + 3.82*3000
= 30,751 pounds

Part b.
Without performing a hypothesis test or a residual plot, we can conclude that the predicted value is in very good agreement with the actual value.

Because we do not have raw measured data, we can neither plot the residuals nor perform a hypothesis test.

In general,
When r² = 1, the agreement is exact.
When r² = 0, there is absolutely no agreement.
A value of r² > 0.9 is considered good.

3 0

3 years ago

What is the answer to x+y=3

Nadusha1986 [10]

Answer:

(x+y)² =(x+y)(x+y) Then you FOIL (First, outer, inner, last)

(x+y)² =(x+y)(x+y) = xx + xy + xy + yy [and when you combine like terms] = x² + 2xy + y²

(x+y)3 = (x² + 2xy + y²)(x+y) Then you FOIL (First, outer, inner, last)

(x+y)3 = (x² + 2xy + y²)(x+y) = x2x +2xxy + xy2 + x2y + 2xyy + y2y [and when you combine like terms] = x3 + 3x2y+ 3xy2 + y3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

URGENT!!! PLEASE HELP

Molodets [167]

Answer: System 1 has an infinite number of solutions and System II has no solutions.

Step-by-step explanation:

If we look at system 1, we see that if we multiply the first equation by 2 and subtract the y value so that its on the same side as x, the equations are the same. That means that no matter the x or y value, it will be a solution.

If we look at system 2, however, we see that if we multiply the top equation by 3, the equations are the exact same except for the fact that the top equation has a -21. This means that no matter the x or y, there will never be a solution.

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3 years ago

Rabies is a viral disease of mammals transmitted through the bite of a rabid animal. The virus infects the central nervous syste

lisabon 2012 [21]

Answer:

(a) The value of <em>x</em> is 0.30.

(b) The probability that a reported case of rabies is not a raccoon is 0.45.

(c) The probability that a reported case of rabies is either a bat or a fox is 0.15.

Step-by-step explanation:

Denote the events as follows:

<em>R</em> = reported case of rabies is a raccoon

<em>F</em> = reported case of rabies is a fox

<em>B</em> = reported case of rabies is a bat

<em>O</em> = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

P (O) = <em>x</em>.

(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, $\sum P(X)=1$

Compute the value of <em>x</em> as follows:

$\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30$

Thus, the value of <em>x</em> is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

$P(A^{c})=1-P(A)$

Compute the probability that a reported case of rabies is not a raccoon as follows:

$P(R^{c})=1-P(R)\\=1-0.55\\=0.45$

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

$P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15$

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

4 0

3 years ago

Part A picture above

-BARSIC- [3]

Answer:

<em>Part A </em>C = (10,5)<em> Part B </em>C. D'(0,10)

Step-by-step explanation:

<em>Part A</em>

Since c is at the point (2,1) in relation to the origin, we can multiply those distances by our scale factor of 5

(2,1) * 5 = (10,5)

The new point C is going to be (10,5)

<em>Part B</em>

If you dilate with a factor of 5 -- relative to the origin -- you have to multiply the distance from <em>the origin</em> by 5.

In this case, point D is already on the y axis, so it's x value wouldn't be affected. Point D is currently 2 units away from (0,0), so we can multiply 2*5 to get 10 -- our ending point is (0,10)

8 0

3 years ago