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vfiekz [6]
3 years ago
13

At a jog a thon you get 1$ at the starting line, 3$ for lap one, 9$ for lap 2 what is the equation

Mathematics
1 answer:
Katarina [22]3 years ago
3 0
6<u>jitterghokrjmi4oiyhj4poiy5u4jyipo4i5yu5y045pyi4y4y4</u>
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ITS AN EMERGENCY PLEASE!
Lady bird [3.3K]
I’m pretty sure the power is 4
3 0
3 years ago
Plutonium-240 decays according to the function L where o
PIT_PIT [208]

Answer:

\boxed{\textbf{1700 yr}}

Step-by-step explanation:

-\dfrac{\text{d}L}{\text{d}t} = kL\\\\\dfrac{dL}{L}=-kdt\\\\\ln L = -kt + C\\\text{At t = 0, L = L$_{0}$, so C = $\ln L_{0}$}\\\ln L = -kt + \ln L_{0}\\\ln L_{0} - \ln L = kt\\\\\ln \dfrac{L_{0}}{L} =kt

Data:

L₀ = 24 g

L = 20 g

k = 0.000 11 yr⁻¹

Calculation:

\ln \dfrac{24}{20} =0.000 11t\\\\\ln 1.2 = 0.000 11t\\\\0.1823 = 0.000 11t\\\\t = \dfrac{0.1823}{0.000 11} = \textbf{1700 yr}\\\\\text{It will take } \boxed{\textbf{1700 yr}}\text{ for the polonium to decay to 20 g}

8 0
3 years ago
Graph the function and answer each of the following questions, f(x) = -3x + 5
olga2289 [7]
A. 5
B. -3/1
C. Negative
D. You have to go down 3 over to the right one from where your y-intercept is.

To plot the y intercept plot (0,5)
To plot the next point go down 3 over 1 to the right from the y-ing
3 0
3 years ago
Divide x^3+2 by x+1<br> long division<br> ppleeease! :)
anzhelika [568]

     Long division:   (x³ + 2)  ÷  (x + 1)


                                        <u>    </u><u>x² –  x  +  1   </u>
      x³ + 0x² + 0x + 2      |    x  +  1
   <u>– x³ –   x²</u>    ⋮       ⋮
          –   x² + 0x     ⋮
          <u>+   x² +   x</u><span>     ⋮</span>
                    +  x + 2
<span>                   </span> <u>–  x – 1</u>
                            + 1


         Quotient:   Q(x) = x² – x – 1;
  
     Remainder:   R(x) = + 1.


I hope this helps. =)

3 0
3 years ago
Q is the midpoint of GH¯¯¯¯¯¯ , GQ=2x+3, and GH=5x−5 . What is the length of GQ¯¯¯¯¯ ?
trasher [3.6K]
The length of GQ is 2 1/3 (two and one-third) where x equals -2/3 (negative two-thirds).
4 0
3 years ago
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