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vfiekz [6]
3 years ago
13

At a jog a thon you get 1$ at the starting line, 3$ for lap one, 9$ for lap 2 what is the equation

Mathematics
1 answer:
Katarina [22]3 years ago
3 0
6<u>jitterghokrjmi4oiyhj4poiy5u4jyipo4i5yu5y045pyi4y4y4</u>
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An item is regularly priced at 90$. Itis now priced at a discount of 30% off the regular price. What is the price now ?
frez [133]
If ur getting 30% off, then ur paying 70%
70% of 90...

0.7(90) = 63 <== discount price
8 0
4 years ago
Read 2 more answers
Order the numbers by value.<br> LEAST to GREATEST<br><br>10<br>√99<br>√75<br>9<br>9.5​
beks73 [17]

Answer:

√75, 9, 9.5, √99, 10

Step-by-step explanation:

that's what I got

4 0
3 years ago
What is the solution to 3x2 + 4x - 8 = 0?
Ber [7]

Answer:

The answer is c

Step-by-step explanation:

3 0
3 years ago
Consider the following operations on the number 8.82 x 10^-2. Without using a calculator, decide which would give a significantl
Ksenya-84 [330]

Correct question is;

Consider the following operations on the number 8.85 x 10^(-2). Without using a calculator, decide which would give a significantly smaller value than 8.85 x 10^(-2), which would give a significantly larger value, or which would give essentially the same value.

A) 8.85 × 10^(-2) + 6.69 × 10^(5)

B) 8.85 x 10^(-2) - 6.69 x 10^(5)

C) 8.85 x 10^(-2) x 6.69 x 10^(5)

D) 8.85 × 10^(-2) ÷ 6.69 × 10^(5)

Answer:

Option A & B yield essentially the same value.

Option C yields a significantly smaller value

Option D yields a significantly larger value

Step-by-step explanation:

Since given value for the operations is in 10^(-2) indices, then let's convert the operations numbers from 10^(5) indices to 10^(-2).

Thus;

6.69 × 10^(5) = (6.69 × 10^(-7)) × 10^(-2)

Thus;

A) 8.85 × 10^(-2) + 6.69 × 10^(5) is now;

8.85 × 10^(-2) + ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 + (6.69 × 10^(-7))] × 10^(-2)

The 10^(-7) indices indicates that the initial value of 8.85 × 10^(-2) would not change much and would essentially be the same

B) 8.85 x 10^(-2) - 6.69 x 10^(5) is now;

8.85 × 10^(-2) - ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 - (6.69 × 10^(-7))] × 10^(-2)

Again the 10^(-7) indices indicates that the initial value of 8.85 × 10^(-2) would not change much and would essentially be the same.

C) 8.85 x 10^(-2) x 6.69 x 10^(5) is now;

(8.85 × 10^(-2)) × ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 × (6.69 × 10^(-7))] × 10^(-2)

When we multiply 8.85 by 6.69 × 10^(-7), the value gotten will be way lower than the initial value of 8.85.

Thus,this operation will give a significantly smaller value.

D) (8.85 × 10-2) ÷ (6.69 × 10^5) is now;

(8.85 × 10^(-2)) ÷ ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 ÷ (6.69 × 10^(-7))] × 10^(-2)

When we carry out the operation:

8.85 ÷ (6.69 × 10^(-7)), it is essentially equal to (8.85 × 10^(7))/6.69.

This means that the new value would be significantly larger than the initial value of 8.85.

Thus,this operation yields a significantly larger value.

4 0
3 years ago
George Martin loves The Beatles. Honestly, who doesn’t? On George’s favorite Spotify playlist, 40% of the songs are by The Beatl
makvit [3.9K]

Answer:

17.5%

Step-by-step explanation:

First of all, see this situation as a cumulative binomial distribution. You have isolated trials with a probability of success. This makes it binomial. The wording of the question "what is the probability of at least half..." makes this cumulative.

There are a few ways to calculate this, and I'm not quite sure which way you're familiar with. I'll show the cumbersome way and use wolfram to make the calculation.

First, I'll calculate the probability for 15 success, given 30 trials.

30c15*0.4^15*0.6^15

Since the question asks for the probability of at least 15 success, I'll have to make a calculation for the probability of 16 successes, then 17, and so on. Then I'll have to add all the probabilities together. So, I'll use wolfram for that (see attached)

7 0
3 years ago
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