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3 years ago

Add or subtrack1. -16 +212.-13--123.-23-(-8)

Mathematics

2 answers:

Paul [167]3 years ago

7 0

Subtract
Add
Add
I hope that help

konstantin123 [22]3 years ago

4 0

Answer:

1. subtract

2. add

3. add

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What are the zeros of the parabola: f(x) = x2 - 7x + 10 (that is, what are the x-intercepts or the points where the graph crosse

evablogger [386]

Answer:

$x=2\ or\ x=5\Rightarrow(2,\ 0)\ \vee\ (5,\ 0)$

Step-by-step explanation:

$f(x)=x^2-7x+10\\\\\text{The zeros of the parabola}\ f(x):\\\\f(x)=0\to x^2-7x+10=0\\\\\left\begin{array}{ccc}a+b=-7\\\\ab=10\end{array}\right\}\Rightarrow a=-2,\ b=-5\\\\x^2-2x-5x+10=0\qquad\text{use the distributive property}\\\\x(x-2)-5(x-2)=0\\\\(x-2)(x-5)=0\iff x-2=0\ \vee\ x-5=0\\\\x-2=0\qquad\text{add 2 to both sides}\\x-2+2=0+2\\\boxed{x=2}\\\\x-5=0\qquad\text{add 5 to both sides}\\x-5+5=0+5\\\boxed{x=5}$

6 0

3 years ago

Read 2 more answers

Determine the equation of the graph, and select the correct answer below. (-4, -1)

Mazyrski [523]

Answer:

First you must find the slope So look on your craft and go over to X and look at where y is looking at why count how many up right or left x is then you will have the slope the slope is always rise over run so how far up and then how far over your why is always gonna be your B so basically you would have a Y=B-x

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3 years ago

Which equation in point-slope form contains the points (6, 2) and (2, 4)? A -4=-1/2(x-6) B y – 4 = –2(x – 2) C y-2=-1/2(x-6)

nlexa [21]

Hello!

The equation for point-slope form is

y - b = m(x - a)

m is the slope
(a, b) is a point the line passes through

We are looking for a equation that follows this

The answer is C because a point the line goes through is (6, 2)

The answer is C

Hope this helps!

5 0

3 years ago

Read 2 more answers

write an equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

dimaraw [331]

The equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is $y - 3 = \frac{-7x}{2}+ \frac{21}{4}$

<h3>Solution:</h3>

Given that we have to write equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

Let us first find the slope of given line AB

The slope "m" of the line is given as:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here the given points are A(-2,2) and B(5,4)

$\text {Here } x_{1}=-2 ; y_{1}=2 ; x_{2}=5 ; y_{2}=4$

$m=\frac{4-2}{5-(-2)}=\frac{2}{7}$

Thus the slope of line with given points is $\frac{2}{7}$

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

$\begin{array}{l}{\text {slope of given line } \times \text { slope of perpendicular bisector }=-1} \\\\ {\frac{2}{7} \times \text { slope of perpendicular bisector }=-1} \\ \\{\text {slope of perpendicular bisector }=\frac{-7}{2}}\end{array}$

The perpendicular bisector will run through the midpoint of the given points

So let us find the midpoint of A(-2,2) and B(5,4)

The midpoint formula for given two points is given as:

$\text {For two points }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right), \text { midpoint } \mathrm{m}(x, y) \text { is given as }$

$m(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Substituting the given points A(-2,2) and B(5,4)

$m(x, y)=\left(\frac{-2+5}{2}, \frac{2+4}{2}\right)=\left(\frac{3}{2}, 3\right)$

Now let us find the equation of perpendicular bisector in point slope form

The perpendicular bisector passes through points (3/2, 3) and slope -7/2

The point slope form is given as:

$y - y_1 = m(x - x_1)$

$\text { Substitute } \mathrm{m}=\frac{-7}{2} \text { and }\left(x_{1}, y_{1}\right)=\left(\frac{3}{2}, 3\right)$

$y - 3 = \frac{-7}{2}(x - \frac{3}{2})\\\\y - 3 = \frac{-7x}{2}+ \frac{21}{4}$

Thus the equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is found out

7 0

4 years ago

IN A CLASS OF 30 STUDENTS 13 OF THEM ARE BOYS WHAT PERCENTAGE ARE GIRLS?

mestny [16]

Class of students - number of students that are boys = numbers of students that are girls

30 - 13 = 17

To change the number of students that are girls into percentage...

17/1 * 1/100 = 17/100

17/100 in a % form = 17%

The percentage of girls in the class is 17%

5 0

4 years ago

Add or subtrack1. -16 +212.-13--123.-23-(-8)​

Add or subtrack1. -16 +212.-13--123.-23-(-8)