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r-ruslan [8.4K]
3 years ago
15

Add or subtrack1. -16 +212.-13--123.-23-(-8)​

Mathematics
2 answers:
Paul [167]3 years ago
7 0
Subtract
Add
Add
I hope that help
konstantin123 [22]3 years ago
4 0

Answer:

1. subtract

2.  add

3. add

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Can anyone please work out question 10 in the picture and clearly explain it? Would appreciate it
kotykmax [81]
9945/ 39= 255
If you were to try to divide 99 by thirty five it would not be a whole. You would be able to multiply 39 by 2 to get 78. 99 subtracted by 78 = 21 you would then carry down the 4. to equal 214 you would then figure out 39 multiplied by 5 is the highest number to figure a 195 you would have 19 left over. Carry down your 5 and would have 195. You would have 195 again and then multiply 39 by 5 and it would equal out to 195. Your answer would then be 255.
6 0
3 years ago
The value of a in the equation ax + y = 5 , if x = 2 and y = 3 is a) – 1 b) 0 c) 1
sasho [114]

Answer:

c) 1

Step-by-step explanation:

=> ax+y = 5

<u><em>Putting x =2, y =3</em></u>

=> a(2)+3 = 5

=> 2a = 5-3

=> 2a = 2

<em>Dividing both sides by 2</em>

=> a = 1

3 0
4 years ago
Read 2 more answers
Find the equivalent expression for 3+2[2p+4t]
Sauron [17]

Answer:

3 + 4p + 8t

Step-by-step explanation:

3+2[2p+4t]

Distribute

3 + 4p + 8t

There are no like terms to combine

7 0
3 years ago
If you had an individual who was gifted and talented in math, and well above the rest of your class, how might you use different
irakobra [83]

Answer:

See explanation below.

Step-by-step explanation:

Having students in the classroom who are at different levels of knowledge, interest, and ability can be managed by differentiated instruction. This method is a way of thinking that provides a framework where the instructor can set students with learning tasks that are at levels appropriate with the abilities and interests of each student. Each student can have a different type of class and different type of instruction with the differentiated instruction way of thinking.

A gifted and talented student might be assigned a higher math course, perhaps based on a math assessment for advanced placement. Then students that need to stay on the typical high school path of Algebra I, Geometry, Algebra II, and Trigonometry can do that.

Gifted students might take an alternate path with honors classes or trajectories involving Pre-Calculus or advanced placement Calculus, for example. In some instances, universities have allowed High School students to obtain college credit for some courses taken during High School.

Hope this helps! Have an Awesome Day!! :-)

6 0
3 years ago
Find the m∠CDE, if m∠BCA = 90° and m∠BAC =57°.<br><br> 33°<br> 43°<br> 57°<br> 67°
garri49 [273]

Answer:

33

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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