4 buses and 167 students
1 bus just 7 students
4x7 = 28
28 students are on 4 buses
167- 28 = 138
138 students had travel in cars
Answer:
The numerical length of JL is 6 units
Step-by-step explanation:
Here, we want to determine the numerical length of JL
Mathematically;
JL = JK + KL
2x + 8 = 5x + 7 + 4
2x + 8 = 5x + 11
5x -2x = 8-11
3x = -3
x = -1
But JL = 2x + 8
JL = 2(-1) + 8 = -2 + 8 = 6
The answer is d because 2+y is the sum of 2 and y and then you multiply it by 5
5x-3=21-x
6x=24
X=4
You simply have to isolate the variable and then divide by 6 so that x is completely alone.
Since jason is currently at 54 feet above sea level and David is 11 feet below sea level the add 11 plus 54 which would give you 65 feet is there distance of elevations