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GREYUIT [131]
2 years ago
15

Paaaa hellllpppp po with solution po sana​

Mathematics
1 answer:
ira [324]2 years ago
6 0
<h2>Solving Equations</h2>

To solve linear equations, we must perform inverse operations on both sides of the equal sign to <em>cancel values out</em>.

  • If something is being added to x, subtract it from both sides.
  • If something is being subtracted from x, add it on both sides.
  • Same with multiplication and division. If x is being divided, multiply. If x is being multiplied, divide.

We perform inverse operations to<em> combine like terms</em>. This means to get x to one side and everything else on the other.

<h2>Solving the Questions</h2><h3>Question 1</h3>

5x+7=15

Because 7 is being added to x, subtract it from both sides:

5x+7-7=15-7\\5x=8

Because x is being multiplied by 5, divide both sides by 5:

\dfrac{5x}{5}=\dfrac{8}{5}\\\\x=\dfrac{8}{5}

Therefore. x=\dfrac{8}{5}.

<h3>Question 2</h3>

7x+4=5x-18

Here, we can group all the x values on the left side of the equation. Subtract 5x from both sides:

7x+4-5x=5x-18-5x\\2x+4=-18

To isolate x, subtract 4 from both sides:

2x+4-4=-18-4\\2x=-22

Divide both sides by 2:

\dfrac{2x}{2}=\dfrac{-22}{2}\\\\x=-11

Therefore, x=-11.

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Greg's football team played 16 games this season and won 12 of them.
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4 0
3 years ago
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Logan is making bookmarks that contain flower petals. He has 95 petals. He uses 3 flower petals for each bookmark. What is the G
Tcecarenko [31]

Answer: The GREATEST number of bookmarks that Logan can make = 31.

Step-by-step explanation:

GIven: Total petals = 95

Number of petals required for each bookmark = 3

Number the number of bookmarks can be prepared from 95 petals = 95 ÷ (Petals required of each bookmark)

= 95÷3

=31\dfrac{2}{3}\ \ \ \approx31\text{    [Round to the nearest whole number.]}

i.e. The GREATEST number of bookmarks that Logan can make = 31.

5 0
3 years ago
Find an equation of the line passing through each of the following pairs of points. a (−3, 1), (0, 3)
Svetlanka [38]

\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-3)}}}\implies \cfrac{2}{0+3}\implies \cfrac{2}{3}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{2}{3}}[x-\stackrel{x_1}{(-3)}]\implies y-1=\cfrac{2}{3}(x+3) \\\\\\ y-1=\cfrac{2}{3}x+2\implies y=\cfrac{2}{3}x+3

5 0
3 years ago
Tina rides the bus to school, Theo bikes to school, and Tony walks to school. Their probabilities of being the first one to scho
Pie

Answer:

Tina is first

Tony is first

Theo is first

Step-by-step explanation:

Events with greater probability are more likely.

Let's put the probabilities in decimal form.

P(Tina is first) = 0.05

P(Theo is first) = %85 = 0.85

P(Tony is first) = 1/10 = 0.1

0.05 < 0.1 < 0.85

The events are listed below from least to most likely.

Tina is first, Tony is first, Theo is first

hope it helps

8 0
3 years ago
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