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1 answer:
<h2>Solving Equations</h2>
To solve linear equations, we must perform inverse operations on both sides of the equal sign to <em>cancel values out</em>.
- If something is being added to x, subtract it from both sides.
- If something is being subtracted from x, add it on both sides.
- Same with multiplication and division. If x is being divided, multiply. If x is being multiplied, divide.
We perform inverse operations to<em> combine like terms</em>. This means to get x to one side and everything else on the other.
<h2>Solving the Questions</h2><h3>Question 1</h3>Because 7 is being added to x, subtract it from both sides:
Because x is being multiplied by 5, divide both sides by 5:
Therefore. .
Here, we can group all the x values on the left side of the equation. Subtract 5x from both sides:
To isolate x, subtract 4 from both sides:
Divide both sides by 2:
Therefore, .
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We have that
<span>p(t)=-3t^2+18t-4
using a graphing tool, we can see the maximum of the graph
(see the attached figure)
A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?
</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)
<span>B) What is the maximum profit?
23 (hundred of thousand of dollars) = 2.300.000 dollars
</span>c) What time will it be two late?
(This is the time when the graph crosses zero and the profits turn into losses )
5.77 years, or an estimate of about 69 months.
<span>p(t)=-3t^2+18t-4
using a graphing tool, we can see the maximum of the graph
(see the attached figure)
A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?
</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)
<span>B) What is the maximum profit?
23 (hundred of thousand of dollars) = 2.300.000 dollars
</span>c) What time will it be two late?
(This is the time when the graph crosses zero and the profits turn into losses )
5.77 years, or an estimate of about 69 months.