-x+3=-3d-3r, for x .

I can't get to get this right can you please help me

monitta

Answer:

$(-7,4]\text{ or }\{x|-7$

Step-by-step explanation:

The domain is the span of x-values covered by the function.

From the graph, we can see that the graph covers all the x-values from x=-7 to x=4.

However, note that closed and open circles. There is an open circle at x=-7, which means that the domain excludes x=-7. However, the circle at x=4 is closed, meaning it is included in the domain.

Therefore, the domain is, in interval notation:

$(-7,4]$

We use parentheses on the left because we do not include -7. And we use brackets on the right because we <em>do </em>include the 4.

And in set notation, this is:

$\{x|-7$

7 0

2 years ago

Read 2 more answers

Simplify the expression where possible. (t 9) -8

makvit [3.9K]

Answer:

$\frac{1}{t^{72}}$ .

Step-by-step explanation:

To solve this problem, we need to simplify the expression $(t^{9})^{-8}$ .

We know that $(x^{a})^{b} = x^{ab}$

Therefore:

$(t^{9})^{-8} =t^{-72} =\frac{1}{t^{72}}$ .

7 0

2 years ago

A) what value represents the 40th percentile of these returns?

Yuki888 [10]

<span>You need to look at the scale of different values and find one which is in the 40th percentile. This means 40 percent are higher and 60 percent are lower than the value you select. This can be done by figuring out the middle and going up a bit.</span>

4 0

2 years ago

It is believed that Lake Tahoe Community College (LTCC) Intermediate Algebra students get less than seven hours of sleep per nig

Kitty [74]

Answer: No , at 0.05 level of significance , we have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

Step-by-step explanation:

Let $\mu$ denotes the average hours of sleep per night.

As per given , we have

$H_0:\mu=7\\H_a:\mu$

, since $H_a$ is left-tailed and population standard deviation is unknown, so the test is a left-tailed t -test.

Also , it is given that ,

Sample size : n= 22

Sample mean : $\overline{x}=7.24$

Sample standard deviation : s= 1.93

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$

i.e. $t=\dfrac{7.24-7}{\dfrac{1.93}{\sqrt{22}}}\approx0.58$

For significance level $\alpha=0.05$ and degree of freedom 21 (df=n-1),

Critical t-value for left-tailed test= $t_{\alpha, df}=t_{0.05,21}=- 1.7207$

Decision : Since the test statistic value (0.58) > critical value 1.7207, it means we are failed to reject the null hypothesis .

[Note : When $|t_{cal}|>|t_{cri}|$ , then we accept the null hypothesis.]

Conclusion: We have sufficient evidence to reject the claim that LTCC Intermediate Algebra students get less than seven hours of sleep per night, on average.

6 0

2 years ago

Find the distance between two points (5,10) and (-4,6)

Helga [31]

Answer:

Explanation:

The formula for calculating the distance between two points is:

d

=

√

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

Substituting the values from the points in the problem gives:

d

=

√

(

−

6

−

3

)

2

+

(

−

4

−

5

)

2

d

=

√

(

−

6

+

3

)

2

+

(

−

4

+

5

)

2

d = √ ( − 3 ) 2+ 1 2

d = √ 9+ 1

d = √ 10

Or

d = 3.162

rounded to the nearest thousandth

7 0

2 years ago