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ipn [44]
3 years ago
7

A driver descends 24 feet in 1 minute. What is his rate of descent in feet per second?

Mathematics
1 answer:
zaharov [31]3 years ago
4 0

0.4 feet per second is the answer.

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I really need help with distributive property
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To “distribute” means to divide something or give a share or part of something. According to the distributive property, multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together.

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Which choices are equivalent to the fraction below? check all that apply 16/36
kenny6666 [7]

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\frac{16}{36} = \frac{8}{18} = \frac{4}{9}

Step-by-step explanation:

\frac{16}{36} = \frac{16/4.5}{36/4.5} = \frac{3.5555}{8} \neq  \frac{3}{8} \\\\\frac{16}{36} = \frac{16/12}{36/12} = \frac{1.3333}{3} \neq  \frac{1}{3} \\\\\frac{16}{36} = \frac{16/9}{36/9} = \frac{1.7777}{4} \neq  \frac{1}{4} \\\\\frac{16}{36} = \frac{16/4}{36/4} = \frac{4}{9} \\\\\frac{16}{36} = \frac{16/7.2}{36/7.2} = \frac{2,2222}{5} \neq  \frac{2}{5} \\\\\frac{16}{36} = \frac{16/2}{36/2} = \frac{8}{18} \\\\

3 0
2 years ago
Write an equation of a parabola that passes through (3,-30) and has x-intercepts of -2 and 18. Then find the average rate of cha
Nookie1986 [14]

Answer:

The equation of the parabola is y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}.  The average rate of change of the parabola is -4.

Step-by-step explanation:

We must remember that a parabola is represented by a quadratic function, which can be formed by knowing three different points. A quadratic function is standard form is represented by:

y = a\cdot x^{2}+b\cdot x + c

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

a, b, c - Coefficients, dimensionless.

If we know that (3, -30), (-2, 0) and (18, 0) are part of the parabola, the following linear system of equations is formed:

9\cdot a +3\cdot b + c = -30

4\cdot a -2\cdot b +c = 0

324\cdot a +18\cdot b + c = 0

This system can be solved both by algebraic means (substitution, elimination, equalization, determinant) and by numerical methods. The solution of the linear system is:

a = \frac{2}{5}, b = -\frac{32}{5}, c = -\frac{72}{5}.

The equation of the parabola is y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}.

Now, we calculate the average rate of change (r), dimensionless, between x = -2 and x = 8 by using the formula of secant line slope:

r = \frac{y(8)-y(-2)}{8-(-2)}

r = \frac{y(8)-y(-2)}{10}

x = -2

y = \frac{2}{5}\cdot (-2)^{2}-\frac{32}{5}\cdot (-2)-\frac{72}{5}

y(-2) = 0

x = 8

y = \frac{2}{5}\cdot (8)^{2}-\frac{32}{5}\cdot (8)-\frac{72}{5}

y(8) = -40

r = \frac{-40-0}{10}

r = -4

The average rate of change of the parabola is -4.

3 0
2 years ago
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