This equation has an infinite number of solutions, so it will be categorized as an identity.
T = 60
please mark me brianliest
the square root is 8.246211251
The square of a prime number is not prime.
a) let x ∈ R, If x ∈ {prime numbers}, then 
∉{prime numbers}
there says that if x is a real and x is in the set of the prime numbers, then the square of x isn't in the set of prime numbers.
b) Prove or disprove the statement.
ok, if x is a prime number, then x only can be divided by himself. Now is easy to see that = x*x can be divided by himself and x, then x*x is not a prime number, because can be divided by another number different than himself
Answer: No.
Reason: (-1, -3) is (x, y) so, let's find -1 on the X scale first. Alright, -1 is in the blue, which is a great start. Now, it's -3 on the Y portion. And when you graph that, it's not in the blue shaded area, so no, it's not a solution. (TIP: Solution is the Shaded Area)
