A) How high up the wall does it reach?
Use the Pythagorean theorem
Height^2 + Base^2 = Hyp^2
H^2+ 2^2 = 4^2 Subtract the 2^2 from both sides
H^2 = 4^2 -2^2 Multiply the square roots of both the numbers
H^2= 16 - 4
H^2 = 12
H= sqrt(12) m
Hope this helps
Answer:
<em>Here</em><em> </em><em>is</em><em> </em><em>your</em><em> </em><em>answer</em><em> </em>
Step-by-step explanation:
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Answer:
It shifted 6 units down
Step-by-step explanation:
Do the graph normally without the k and compare them side by side.
In ΔCAD and ΔCBD,
CD = CD [ Common side ]
AD = BD [ CD is the perpendicular "bisector" of AB ]
∠CDA = ∠CDB [ CD is the "perpendicular" bisector of AB ]
Thus, ΔCAD and ΔCBD are congruent triangles. [ SAS congruency ]
If these triangles are congruent, then AC = BC.
2x = 3x -10
x = 10.
Answer: y = 4x + 11
Step-by-step explanation:First, you put the equation into the standard “slope/intercept” form.
4x -y = 2 subtract 4x from both sides ; -y = -4x + 2 Multiply by -1 :
y = 4x - 2
In this standard form we see that the slope of the line (coefficient of x) is 4. ANY line parallel to this one must thus also have a slope of 4.
y = 4x - a (generic)
ANY other combination of slope multiples and constant terms will therefore also be lines parallel to this one. The one that passes through a specific point will simply have a different constant term.
We find this by putting our point value into the equation:
3 = 4(-2) + a ; 3 = -8 + a ; a = 11
Thus, our “parallel line equation” through the point (-2,3) is:
y = 4x + 11
