All categories

3 years ago

The actual mechanical advantage of a machine

Mathematics

2 answers:

RoseWind [281]3 years ago

7 0

1. D
2.B
3.C
4.B
5.C

Hope this helps

Vikentia [17]3 years ago

4 0

The answer is D just took the test.

You might be interested in

Circle A has a diameter of 9 cm Circle B has a radius of 5 cm which Circle has the largest circumference and about how many cent

Alexandra [31]

Answer:

circle b and it is bigger by 1 centimeter

Step-by-step explanation:

since circle b has a radius of 5 and radius is have of the diameter you have to do 5+5 to get the diameter when you do that you get 10 and then you have to subtract circle a diameter which is 9 from circle b diameter which is 10 so 10-9 is 1

4 0

3 years ago

In the diagram, AITP - ANGO. Find the values of x and y. y = X=

Zepler [3.9K]

Answer:

x = 25, y = 9

Step-by-step explanation:

Since the triangles are congruent then corresponding angles and sides are congruent, thus

∠ O = ∠ P , substitute values

6y - 14 = 40 ( add 14 to both sides )

6y = 54 ( divide both sides by 6 )

y = 9

and

NG = IT , that is

x - 2y = 7 ( substitute y = 9 into the equation )

x - 2(9) = 7

x - 18 = 7 ( add 18 to both sides )

x = 25

7 0

3 years ago

15 points!!

saw5 [17]

Answer:

If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the triangles are congruent.

Step-by-step explanation:

5 0

3 years ago

What is one and a half added to three and a half?

mars1129 [50]

One and a half = 1.5
Three and a half = 3.5
1.5 + 3.5 = 5.

6 0

3 years ago

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :