Answer: Option A.
Step-by-step explanation:
You need to use this formula for calculate the surface area of the right cylinder:

Where "r" is the radius and "h" is the height.
You can identify in the figure that:

Knowing this, you can substitute these values into the formula
, therefore you get that the surface area of this right cylinder is:


Answer:
this isn’t a 100% guaranteed correct answer but maybe the second option saying “PQ and P’G’ are parallel”
(i’m doing the test rn)
5 1/2 * 2 1/3 =
11/2 * 7/3 =
77/6 =
12 5/6 <===