Daniel Trumpe has computed the EOQ for a product he sells to be 400 units. However, due to recent events he has a cash flow prob
1 answer:
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We know that
The arrangement forms an isosceles triangle with equal legs of 8 miles.
The angle between the legs is equal to
°
Therefore, the other two angles are
Angles = (180-60)/2 = 120/2 = 60°
It can, therefore, be noted that all angles are equal and thus the resulting triangle is actually an equilateral triangle and thus all the sides are equal.
Hence
the answer is
the distance between the two ships is 8 miles apart
alternative Method
Applying the law of cosines
<span>c²=a²+b²-2*a*b*cos C
</span>where
a=8 miles
b=8 miles
C is the angle between the legs-------> 123-63------> 60 degrees
c is the distance between the two ships
so
c²=8²+8²-2*8*8*cos 60------> c²=64-------> c=√64------> c=8 miles
The arrangement forms an isosceles triangle with equal legs of 8 miles.
The angle between the legs is equal to
Therefore, the other two angles are
Angles = (180-60)/2 = 120/2 = 60°
It can, therefore, be noted that all angles are equal and thus the resulting triangle is actually an equilateral triangle and thus all the sides are equal.
Hence
the answer is
the distance between the two ships is 8 miles apart
alternative Method
Applying the law of cosines
<span>c²=a²+b²-2*a*b*cos C
</span>where
a=8 miles
b=8 miles
C is the angle between the legs-------> 123-63------> 60 degrees
c is the distance between the two ships
so
c²=8²+8²-2*8*8*cos 60------> c²=64-------> c=√64------> c=8 miles
Answer:
D. 22,417 feet
Step-by-step explanation:
Fine the diagram in the attachment for proper elucidation. Using the SOH, CAH, TOA trigonometry identity to solve for the distance (x) from the plane (P) to the observer (O), the longest side x is the hypotenuse and the side facing the angle of elevation is the opposite.
Hypotenuse = x and Opposite = 15,000feet
According to SOH;
Hence the distance (x) from the plane P to the observer O is approximately 22,417 feet