That would be DF is congruent to DE ( first choice)
( they are both = sqrt(2^2 + 3^2)
Well 1000 for his birthday then subtract 25 each week, w, should be 1000-25w if i am not mistaken.
Answer:
25πm²
Step-by-step explanation:
Circumference of the circular sculpture = πd
d is the diameter
Given
Circumference = 10π metres
Substitute into the formula
10π = πd
10 = d
d = 10m
Area of the sculpture = πd²/4
area of the sculpture = π(10)²/4
area of the sculpture = 100π/4
area of the sculpture = 25π m²
Hence the measurement closest to the area of the sculpture in square meters is 25πm²
The answer is reduction. This can be found by the size and number differences in the two quadrilaterals.