I think the answer to 14 is J
The graph suggests that the two lines meet at 
If this is true, that point must belong to both lines.
To check this, plug
in both equations, and you must get
once you simplifiy all the numbers.
In the first equation we have

In the second,

That is a 30 60 90 triangle
The "short" side (DE) equals the middle side (FE) times (1 / sq rt(3))
short side = 8 * sqrt(3) * (1 / sq rt(3) = 8
Hypotenuse (DF) is 2 times the short side which equals 16.
Source:
http://www.1728.org/trig2.htm
Answer:
y≤x²+4x-1.
Step-by-step explanation:
1) to define the equation of the given graph; it is y=x²+4x-1 (its vertex is (-2;-5));
2) to define inequation accorging to the given graph (the area outside of the parabola means ≤).