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Pachacha [2.7K]
2 years ago
11

What is the value of x?

Mathematics
1 answer:
adelina 88 [10]2 years ago
4 0

This is an equilateral triangle, which is a triangle that has 3 congruent/equal sides and 3 congruent angles.


To find "x", you can set the sides equal to each other because they are suppose to be the same length (you can just do two sides because all of the sides are the same)

[Side AB = Side BC]

4x - 10 = 3x + 2     Subtract 3x on both sides

x - 10 = 2         Add 10 on both sides

x = 12


[proof]

Side AB:

4x - 10    Plug in 12 for x

4(12) - 10 = 48 - 10 = 38


Side BC:

3x + 2     Plug in 12 for x

3(12) + 2 = 36 + 2 = 38


Side AC:

5x - 22      Plug in 12 for x

5(12) - 22 = 60 - 22 = 38




This is also an equilateral triangle (the tick marks show that the sides are the same)

A triangle is 180°. So the three angles add up to 180°.

Since this is an equilateral triangle, all the angles should be the same.

Each angle is 60°

[60° + 60° + 60° = 180°   or you could have divided 180 by 3 = 60]


Now that you know each angle is 60°, you can do:

(2x - 4)° = 60°

2x - 4 = 60    Add 4 on both sides

2x = 64    Divide 2 on both sides

x = 32


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Exact form:

(36 + 9√ 7 + 4√2 + √14) / 9

or

about 7.69

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3 years ago
Two consecutive positive numbers are such that the sum of their squares is 113. find the two numbers
Naya [18.7K]

Answer: 7 and 8

<u>Step-by-step explanation:</u>

Let x represent the first number, then x + 1 is the other number.

(x)² + (x + 1)² = 113

x²  +  x² + 2x + 1 = 113    <em>expanded (x + 1)²</em>

2x² + 2x + 1 = 113          <em>added like terms</em>

2x² + 2x - 112 = 0        <em>subtracted 113 from both sides</em>

x² + x - 56 = 0 <em>           divided both sides by 2</em>

(x + 8) (x - 7) = 0        <em>factored polynomial</em>

x + 8 = 0   x - 7 = 0    <em>applied zero product property</em>

x = -8     x = 7  <em>          solved for x</em>

  ↓

not valid since the restriction is that x > 0 <em>(a positive number)</em>

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8 0
3 years ago
your grades on tests 1 2 and 4 are 82 76 and 90. unfortunately you cut the third test and received a 0. If you have one test lef
Dmitrij [34]

Answer:  No, he can't pass the course.

Explanation:

Since we have given that

Marks on tests 1, 2, and 4 are given by

82, 76, 90 respectively.

Unfortunately, he cut the third test and receive a 0.

According to question, we have given that passing grade for the course is 70, and his one test left to take ,

Let the marks obtained in fifth test be x

So,

\frac{82+76+90+0+x}{5}=70\\\\248+x=5\times 70=350\\\\x=350-248\\\\x=102

And it is not possible to get 102 over 100.

so, he can't still pass the course.

Hence, No, he can't pass the course.

8 0
3 years ago
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