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Bond [772]
3 years ago
9

How much has the value of y changed between the points (–8, 4) and (8, –4)?

Mathematics
1 answer:
Klio2033 [76]3 years ago
6 0
The y value has changed by 8
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Someone help i'll give brainliest to right answer!
Bogdan [553]

Answer:

145

Step-by-step explanation:

angles in a pentagon add up to equal 540

Hence, 110 + 90 + 80 + 115 + v = 540

( note that we just created an equation that we can use to solve for v )

We now solve for v using the equation created

110 + 90 + 80 + 115 + v = 540

step 1 combine like terms

110 + 90 + 80 + 115 = 395

we now have 395 + v = 540

step 2 subtract 395 from each side

540 - 395 = 145

395 - 395 cancels out

we're left with v = 145

8 0
2 years ago
The price of milk increased from $2 to $2.50. What is the percent of change for the price of milk?
Alina [70]

25.00%

Or

25c

Have a Merry Christmas!

5 0
3 years ago
A submarine was situated 800 feet below sea level. If it ascends 350 feet, what is its
coldgirl [10]

Answer:

450 feet below sea level

5 0
3 years ago
Michael is packing his bags for his vacation. He has 5 unique shirts, but only 4 fit in his bag. How many different groups of 4
DiKsa [7]

Answer:

12

Step-by-step explanation:

I think you have to use the product rule for counting- which is where you multiply the two numbers. I'm not sure if this is right but I hope I helped

3 0
3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
4 years ago
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