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Alina [70]
3 years ago
6

HELPPPP I NEED HELPPPPP

Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0

Answer:

2/4

Step-by-step explanation:

kenny6666 [7]3 years ago
3 0

Answer:

IM pretty sure its 50% percent because half is 50 and it looks like a full circle or you could say 2/4

Step-by-step explanation:

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Write a problem to describe the number line. plzz helpp me
sammy [17]

Answer:

all  neg

Step-by-step explanation:

6 0
3 years ago
ANALYZE A PROBLEM Describe the x-values for which (a) f is increasing (b) f is decreasing, (c) f (x) > 0 and (d) f (x) < 0
Karolina [17]

The analysis of the graph, that has x-intercepts of (0, 2), and (0, 5), we get;

a. The function increases when x > 4

b. The function decreases when x < 4

c. The function is greater than zero when x < 3, and x > 5

d. The function is less than zero when 3 < x < 5

<h3>What is a point where a function is increasing?</h3>

The location of a point where a function is increasing is where the slope of the function is larger than zero.

The description of the graph of the function are as follows;

The shape of the function  = Concave upwards

The coordinates of the vertex of the function = (4, -5)

The region where the function is decreasing is from -∞ to 4

The region where the function is decreasing is therefore; x < 4

At the vertex, (4, -5), the slope of the function is zero, therefore;

Therefore, the function is increasing where x > 4

The x-intercepts are at point (0, 3) and (0, 5)

Therefore, the function is greater than zero when x < 3, and when x > 5

The function is less than zero in the range 3 < x < 5

Learn more about the graph of functions here:

brainly.com/question/16924356

#SPJ1

7 0
2 years ago
In his free time, Gary spends 11 hours per week on the Internet and 11 hours per week playing video games. If Gary has five hour
Tpy6a [65]

Answer:

62.8% OR 0.628

Step-by-step explanation:

11 hours playing video games

11 hours on the Internet

11 + 11 = 22

5 hours of free time each day

7 days in a week

5 x 7 = 35

22/35 hours are spent

That is 0.62857142857 or I just mathmatically rounded to 0.628

0.628 into a fraction is 62.8%

6 0
3 years ago
Is it possible to divide 15 by a mixed number and get a quotient that is greater than 15? Explain.
shutvik [7]
Mixed numbers are greater than one it wouldn't make sense for a mixed number to be less than one, because then it would just be a regular fraction.

<span>You can only get a bigger number if you divide by a number less than one. That means you can't divide 15 by a mixed number and get a bigger number.</span>
4 0
3 years ago
Solve the equation using the substitution u = y/x. When u = y/x is substituted into the equation, the equation becomes separable
bekas [8.4K]

Answer:

\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}

Step-by-step explanation:

First step: I'm going to solve our substitution for y:

u=\frac{y}{x}

Multiply both sides by x:

ux=y

Second step: Differentiate the substitution:

u'x+u=y'

Third step: Plug in first and second step into the given equation dy/dx=f(x,y):

u'x+u=\frac{x(ux)+(ux)^2}{3x^2+(ux)^2}

u'x+u=\frac{ux^2+u^2x^2}{3x^2+u^2x^2}

We are going to simplify what we can.

Every term in the fraction on the right hand side of equation contains a factor of x^2 so I'm going to divide top and bottom by x^2:

u'x+u=\frac{u+u^2}{3+u^2}

Now I have no idea what your left hand side is suppose to look like but I'm going to keep going here:

Subtract u on both sides:

u'x=\frac{u+u^2}{3+u^2}-u

Find a common denominator: Multiply second term on right hand side by \frac{3+u^2}{3+u^2}:

u'x=\frac{u+u^2}{3+u^2}-\frac{u(3+u^2)}{3+u^2}

Combine fractions while also distributing u to terms in ( ):

u'x=\frac{u+u^2-3u-u^3}{3+u^2}

u'x=\frac{-u^3+u^2-2u}{3+u^2}

Third step: I'm going to separate the variables:

Multiply both sides by the reciprocal of the right hand side fraction.

u' \frac{3+u^2}{-u^3+u^2-2u}x=1

Divide both sides by x:

\frac{3+u^2}{-u^3+u^2-2u}u'=\frac{1}{x}

Reorder the top a little of left hand side using the commutative property for addition:

\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}

The expression on left hand side almost matches your expression but not quite so something seems a little off.

5 0
3 years ago
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