Answer:
Step-by-step explanation:
the a = 30
Answer:
SQUARE
Step-by-step explanation:
If Quadrilateral MNPQ has vertices M(4,0), N(0,6), P(-4,0) and Q(0, -6).
Find the following MN, NP, PQ and MQ
Using the formula for calculating the distance between two points
MN = √(6-0)²+(0-4)²
MN = √6²+4²
MN = √36+16
MN = √52
MN = 2√13
NP = √(0-6)²+(-4-0)²
NP = √6²+4²
NP = √36+16
NP = √52
NP = 2√13
PQ = √(-6-0)²+(0-(-4))²
PQ = √6²+4²
PQ = √36+16
PQ = √52
PQ = 2√13
MQ = √(-6-0)²+(0-4)²
MQ = √6²+4²
MQ = √36+16
MQ= √52
MQ = 2√13
Since the length of all the sides are equal, hence the shape is a SQUARE
Answer: The cats cost more
also there is a typo
Step-by-step explanation:
I bought 1 dog and 3 cats a total cost of $7.75. the three cats cost more so in all the cats must cost 3.56$
It would be 455 inches because you divide 5/2 and it is 2.5 then you multiply it by 182 which is 455
Answer:
The required point is P(-7,
) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7
Step-by-step explanation:
Given equation of line is 2x-6y=7
To find point on graph whose x-coordinate twice the y-coordinate:
Let y be y-coordinate of point
Hence, x-coordinate of point will be 2y
The required point is P(2y,y) on equation of line 2x-6y=7
Now,
2x-6y=7
2(2y)-6y=7
-2y=7
y=
Thus,
The required point is P(-7,)
Note: Figure show equation of line red line and point P as blue dot.
