The sum of two consecutive even integers is at most seven more than half the sum of the next two consecutive even integers
two consecutive even integers: n, n+2
next two consecutive even integers n+4, n+6
n+(n+2) >= 7+1/2(n+4 +n+6)
combine like terms
2n+2 >= 7 +1/2(2n+10)
distribute 1/2
2n+2 >= 7+n+5
2n+2>= n+12
subtract n from each side
n+2>= 12
subtract 2 from each side
n>10
4 integers : 10, 12 ,14, 16
Answer:
It is not factorable.
Step-by-step explanation:
It is not factorable with rational numbers.
You can determine this by finding zeros of quadratic function,
.
Which eliminates first and third option.
Now we have up and down parabolas left.
If we factor 
we find that the coefficient before 
determines how it is turned, since its positive its an upward turned parabola hence the answer is the last graph.
Hope this helps.
Answer:
a reflection and then a translation
Step-by-step explanation:
