To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
Step-by-step explanation:
take angle C as reference angle
using cos rule
cos C=adjacent/hypotenuse
cos C=21/75
cos C=0.28
C=
0.28
C=73.7 degree
Answer:
x = 3
Step-by-step explanation:
6.78x - 5.2 = 4.33x + 2.15
6.78x - 4.33x = 5.2 + 2.15
2.45x = 7.35
x = 7.35/2.45
x = 3
Thus, The value of x is 3
<u>-TheUnknown</u><u>Scientist</u>
answer:
y=5.5x
explanation:
rise over run=rise/run= x/y
for every t shirt or "y" multiply 5.5 and it will give u the total cost or"x"
