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Sliva [168]
3 years ago
12

Chapter : Circles 1 question

Mathematics
1 answer:
erica [24]3 years ago
5 0
We can solve this question in 2 ways: either using degrees or converting the degrees into radians.

Since, the question says degrees itself and there is no specification of using radians only, so I have solved it using degrees itself.

Part (a):

Perimeter of sector ORS = 2*Radius + Arc RS = 2*21 + 60*  \frac{ \pi }{180} *21 =  \frac{ \pi }{3} *21 = 7 \pi

Part (b):

Area of sector ORS = \frac{60}{360} * \pi * 21^{2} =  \frac{1}{6} * \pi *21*21=  \frac{147}{2} \pi

Area of sector POQ = \frac{36}{360} *  \pi * 14^{2} =  \frac{1}{10} *  \pi * 196 =  \frac{196}{10}  \pi

Thus, area of shaded region
= Area of sector ORS - Area of sector POQ

= \frac{147}{2} \pi - \frac{196}{10} \pi =  \frac{735 - 196}{10}  \pi =  \frac{539}{10}  \pi = 53.9 \pi

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cindy is training for a race. she ran 3/5 mile each day for 7 days. how many miles did she ran in those 7 days
anyanavicka [17]
Multiply the two numbers

3/5*7/1= 21/5

21/5= 4 1/5 miles

Answer: 4 1/5 miles
3 0
3 years ago
In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0
2 years ago
2. A CD is marked with a sale sticker saying it is 56% off. The original price is $10.17. What is the sale price?​
klasskru [66]

Answer:

4.4748

Step-by-step explanation:

$10.17- 56% = $4.4748

just round it of to 2 decimals

6 0
3 years ago
EASY MATH ILL GIVE BRIANLIST PLEASE HELP, IT HAS TO BE CORRECT
Ipatiy [6.2K]
Here is the answer and steps. Answer:-3/5

3 0
3 years ago
Read 2 more answers
Which is correct? A.b.c.
Hatshy [7]
By geometry, there is a relationship between the tangent PA and the segments PB and PE, namely
PA^2=PB*PE
so 
PE=PA^2/PA=6^2/4=9
BE=PB-PE=9-4=5
6 0
3 years ago
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