Question

Y=x+2 2x-y=-4 Solve the systems of equations

Answer 1

Answer: x = -2, y = 0

Step-by-step explanation:

$y=x+2\\2x-y=-4$

Substitute y = x+2 in $2x-y=-4$

Then we get, $2x-(x+2)=-4$

$2x-x-2=-4\\x-2=-4\\x=-4+2\\x=-2$

Then substitute x = -2 in any equations, just only one equation. For me, I'd substitute x = -2 in y = x+2

$y=-2+2y=0$

So the answer is x = -2 and y = 0

Answer 2

Answer:

Step-by-step explanation:

Given that,

y=x+2 equation 1

2x-y=-4 equation 2

This is a simultaneous equation.

Substitute equation 1 into equation 2

2x-y=-4. Since y=x+2

2x-(x+2) = -4

2x-x-2 = -4

x-2 = -4

x = -4+2

x = -2

Also from equation 1

y=x+2

Since x=-2

y=-2+2

y=0

Then, solution (x, y) = (-2,0)