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3 years ago

Y=x+2 2x-y=-4 Solve the systems of equations

Mathematics

2 answers:

Simora [160]3 years ago

6 0

Answer: x = -2, y = 0

Step-by-step explanation:

$y=x+2\\2x-y=-4$

Substitute y = x+2 in $2x-y=-4$

Then we get, $2x-(x+2)=-4$

$2x-x-2=-4\\x-2=-4\\x=-4+2\\x=-2$

Then substitute x = -2 in any equations, just only one equation. For me, I'd substitute x = -2 in y = x+2

$y=-2+2y=0$

So the answer is x = -2 and y = 0

larisa86 [58]3 years ago

4 0

Answer:

Step-by-step explanation:

Given that,

y=x+2 equation 1

2x-y=-4 equation 2

This is a simultaneous equation.

Substitute equation 1 into equation 2

2x-y=-4. Since y=x+2

2x-(x+2) = -4

2x-x-2 = -4

x-2 = -4

x = -4+2

x = -2

Also from equation 1

y=x+2

Since x=-2

y=-2+2

y=0

Then, solution (x, y) = (-2,0)

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identify and equation in point-slope form for the line perpendicular to y=-1/2x-7 that passes through (-3,-2)

bazaltina [42]

Answer:

y +2 = 2(x +3)

Step-by-step explanation:

The equation in point-slope form for a line with slope m through point (h, k) is ...

y -k = m(x -h)

The slope of your given line is the coefficient of x, -1/2. The slope of a perpendicular line will be the negative reciprocal of that: -1/(-1/2) = 2. So, you have m = 2, (h, k) = (-3, -2), and your desired equation is ...

y -(-2) = 2(x -(-3)) . . . . . . which can be simplified to ...

y +2 = 2(x +3)

8 0

3 years ago

⎧

d1i1m1o1n [39]

<u>Given</u>:

The given expression to find the nth term of the sequence is $d(n)=d(n-1) \cdot (-5)$

The first term of the sequence is $d(1)=8$

We need to determine the third term of the sequence.

<u>Second term:</u>

The second term of the sequence can be determined by substituting n = 2 in the nth term of the sequence.

Thus, we have;

$d(2)=d(2-1) \cdot (-5)$

$d(2)=d(1) \cdot (-5)$

$d(2)=8 \cdot (-5)$

$d(2)=-40$

Thus, the second term of the sequence is -40.

<u>Third term:</u>

The third term of the sequence can be determined by substituting n = 3 in the nth term of the sequence.

Thus, we have;

$d(3)=d(3-1) \cdot (-5)$

$d(3)=-40 \cdot (-5)$

$d(3)=120$

Thus, the third term of the sequence is 120.

7 0

2 years ago

Read 2 more answers

Evaluate help please!

UNO [17]

<h2><u>ABSOLUTE VALUE</u></h2>

The absolute value of a number is the distance from 0 to that number. The distance is positive, hence, the absolute value is always a positive number.

<h3>Exercise</h3>

Replace the value of x:

$| x - 8 |$

$| -4 - 8 |$

$| -12 | = \large{\boxed{12}}$

The absolute value of a number is the numerical value of the number, without regard to its sign.

<h3><u>Answer.</u> 12</h3>

3 0

2 years ago

What are the weights (in Newton’s) for the given masses 22.1,33.5,41.3,59.2,78

Blababa [14]

Answer:

1. 216.8 N

2.328.635 N

3. 405.153 N

4. 580.752 N

5. 765.18 N

Step-by-step explanation:

1. Let the mass is 22.1 kg, then the weight in Newton will be (22.1 × 9.81) = 216.8 N {Where acceleration due to gravity is 9.81 m/sec²}

2. Let the mass is 33.5 kg, then the weight in Newton will be (33.5 × 9.81) = 328.635 N {Where acceleration due to gravity is 9.81 m/sec²}

3. Let the mass is 41.3 kg, then the weight in Newton will be (41.3 × 9.81) = 405.153 N {Where acceleration due to gravity is 9.81 m/sec²}

4. Let the mass is 59.2 kg, then the weight in Newton will be (59.2 × 9.81) = 580.752 N {Where acceleration due to gravity is 9.81 m/sec²}

5. Let the mass is 78 kg, then the weight in Newton will be (78 × 9.81) = 765.18 N {Where acceleration due to gravity is 9.81 m/sec²}

(Answer)

4 0

3 years ago

Cos^2 2x−cos^2 6x=sin4x sin8x<br> please help me prove it

Olin [163]

Cos² 2x = (1+cos 4x )/2
cos² 6x = (1+cos 12x)/2
subtract to get 1/2 (cos 4x - cos 12x )
= 1/2 (2 sin 4x sin 8x ) as cos A - cos B = 2 [ sin (A+B)/2 sin (A-B)/2 ]
so the answer

4 0

2 years ago